chelseajjc95 said:I have this problem with understanding this specific notation could someone explain this notation & figure out how to solve this problem!?
Suppose P(Q)=5/31 , P(R)= 7/31 , P(Q intersect R)=3/31
Find the value of:
A) P(Q') B) P(Q union R) C) P(R')
If you really have no idea what the notations even mean where in the world did you get this question?chelseajjc95 said:I have this problem with understanding this specific notation could someone explain this notation & figure out how to solve this problem!?
Suppose P(Q)=5/31 , P(R)= 7/31 , P(Q intersect R)=3/31
Find the value of:
A) P(Q') B) P(Q union R) C) P(R')
P(Q') represents the probability of the complement of event Q. In other words, it is the probability that event Q does not occur.
P(Q union R) is calculated by adding the individual probabilities of events Q and R, and then subtracting the probability of their intersection.
P(Q') and P(R') represent the probabilities of two different events. P(Q') is the probability of the complement of event Q, while P(R') is the probability of the complement of event R. These probabilities may be different depending on the specific events.
No, P(Q union R) cannot be greater than 1. The probability of an event can never exceed 1, as it represents the likelihood of that event occurring.
P(R) and P(R') are complementary probabilities, meaning that they add up to 1. In other words, if the probability of event R occurring is P(R), then the probability of event R not occurring is P(R') = 1 - P(R).