Find Period of Pendulum's Oscillation with 1-60 Degrees

  • Thread starter Thread starter KitusFanaticus
  • Start date Start date
  • Tags Tags
    Period
Click For Summary

Homework Help Overview

The discussion revolves around determining the period of oscillation for a pendulum described by a nonlinear differential equation, specifically \(\ddot\theta = \left(\frac{-g}{l}\right)\sin(\theta)\), for initial angles ranging from 1 to 60 degrees. Participants are exploring the implications of not using the small angle approximation in their analysis.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the challenges of solving the nonlinear ordinary differential equation (ODE) analytically and suggest numerical methods as alternatives. There are inquiries about using software like Maple for numerical solutions, and some participants express uncertainty about the correct application of boundary conditions in their calculations.

Discussion Status

The conversation is ongoing, with participants sharing insights about numerical methods and boundary conditions. Some guidance has been offered regarding the use of Euler's method and the importance of expressing solutions in terms of sine and cosine functions. However, there is no explicit consensus on the best approach to find the period of oscillation.

Contextual Notes

Participants note that the problem's constraints include avoiding the small angle approximation until a later part of the assignment, which adds complexity to the analysis. There is also mention of needing to account for errors in approximations when comparing results from different methods.

KitusFanaticus
Messages
8
Reaction score
0
Hello,
I have never taken a differential equations class. I have this problem that I could really use some help on.

Thx

Homework Statement


A pendulum' motion is the following equation [tex]\ddot\theta = (\frac{-g}{l})\sin(\theta))[/tex]

I need to find the period of oscillations for various starting angles between 1 and 60 degrees. I am not to approximate [tex]\sin(\theta) = (\theta)[/tex] (that is for a later part.)

Homework Equations


?

The Attempt at a Solution


I don't know how to solve the D.E. The Boas book says its not solvable. I thought that the period would be between times where the acceleration is 0... so I set [tex]\ddot\theta=0[/tex], but didnt get very far with that.

I need to use Maple or some sort of Euler engine? I am clueless about this. Please help me, thank you.

Homework Statement


Homework Equations


The Attempt at a Solution

 
Last edited:
Physics news on Phys.org
You can't solve the ODE analytically without the small angle approximation because it is a nonlinear coefficient. I am not familiar with Maple or Euler engine, but I know that Maple has numerical options. Yes, try solving it numerically with Maple or Euler(?).
 
The other option is to disregard the profs advice and solve for amall angles and by Taylor's expansion account for the error accumulation. My hunch is that the point here is to show up conventional math by numerical solutions.
 
denverdoc said:
The other option is to disregard the profs advice and solve for amall angles ...
No, I can't do that... Thats the second part of the problem. Then for the third part I have to state where the small angle approximation breaks down (using the first two parts).

So, here is where I am at... I need to solve this thing numerically somehow. I messed with Maple a bit and couldn't figure out how to do it. I will try more tomorrow but if somebody has any hints on how I could solve this numerically I would *greatly* appreciate it.

So, if/when I get this numerical solution, I will have a function of t, [tex]\theta (t)[/tex] = something, right? Then I would take the derivative, set that equal to zero to find the times and thus get the period?

Sorry if that didnt make sense, I am not real versed in the subject. As I said I have never taken Diff Eq, but am wishing I had.
 
Once you get your numerical solution, you can find the period by observation. How much time passes between each time [itex]\theta = 0[/itex].

You can use a variation of the http://en.wikipedia.org/wiki/Euler_method" is much better.
 
Last edited by a moderator:
Ok, I have used the Euler method and found the period to be roughly 2 second.

Now I need to make the small angle approximation, and compare the results.

I make the approximation and solve the differential equation to get [tex]\theta(t) = \alpha e^{i\sqrt{\frac{g}{L}}t}+\beta e^{-i\sqrt{\frac{g}{L}}t}[/tex]

Now, the boundary condition are [tex]\dot\theta(0) = 0[/tex] and [tex]\theta (0) = \theta _0[/tex].

This gives me a the function [tex]\theta (t) = \frac{\theta_0}{2}i\sqrt{\frac{g}{L}}*(e^{i\sqrt{\frac{g}{L}}t} -e^{-i\sqrt{\frac{g}{L}}t}[/tex])

But there are no zeros for this save the case where t=0 are there?!?

Where have I gone wrong?
 
Huh? What are you asking about?

I think you made a mistake using the boundary conditions.
[tex]\dot{\theta} = \alpha \omega e^{i \omega t} - B \omega e^{-i \omega t}[/tex]
so
[tex]0 = \alpha i \omega - \beta i \omega[/tex]
omega is non-zero so
[tex]\alpha = \beta[/tex]

and the first condition shows that
[tex]\alpha + \beta = \theta_0[/tex]
or
[tex]2 \alpha = \theta_0[/tex]

Also, do you really care about the complex solutions? I would just take the real components and write the equation as [tex]\theta(t) = c_1 sin \omega t + c_2 cos \omega t[/tex] where [tex]\omega = \sqrt{\frac{g}{l}}[/tex].
 
Ok I find the function to be [tex]\theta (t) = \frac{\theta_0}{2} (exp (i \sqrt\frac{g}{L} t) + (exp (-i \sqrt\frac{g}{L} t)[/tex]

Now to find the period of oscillation I need to find the times between where [tex]\theta (t) = 0[/tex], which only occurs at t=0...

Any help on how to find these periods? Thx.
 
Are you aware of Euler's formula at all? If not, Euler's formula states that
[tex]e^{i\theta} = cos\theta + isin\theta[/tex]
in your case
[tex]exp{i \sqrt{\frac{g}{l}} t} = cos\sqrt{\frac{g}{l}t} + isin \sqrt{\frac{g}{l}t}[/tex]

You can write your exponentials in terms of sines and cosines. In your current state, you will have both a complex solution and a real solution, though you can get just the real solutions if needed/wanted. Once you have your solution in terms of sines and cosines I assume, you seem to be at a pretty good level, you know how to find the period.
 

Similar threads

Replies
1
Views
1K
Replies
5
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 28 ·
Replies
28
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K