Find Poisson's Ratio of Aluminum from Torsion and Tensile Tests

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SUMMARY

The discussion focuses on calculating Poisson's Ratio for aluminum using data from torsion and tensile tests. The torsion test revealed a shear modulus (G) of 4.60x106 psi, while the tensile test indicated a modulus of elasticity (E) of 12.2x106 psi. Poisson's Ratio (v) can be derived using the formula G = E/(2*(1+v)). This relationship allows for the determination of Poisson's Ratio based on the provided modulus values.

PREREQUISITES
  • Understanding of shear modulus and modulus of elasticity
  • Familiarity with strain concepts in material science
  • Basic knowledge of torsion and tensile testing methods
  • Ability to manipulate algebraic equations
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Material scientists, mechanical engineers, and students studying material properties will benefit from this discussion, particularly those interested in the mechanical behavior of aluminum.

JPKelly
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1. Torsion test showed aluminum to have shear modulus of 4.60x10^6psi. Under a tensile test, the same specimen showed a modulus of elasticity of 12.2x10^6psi. Find Poisson's Ratio.



2. Poisson's Ratio=lateral strain/axial strain



3. The ratio is a function of both strains. The equations for strain do not have any modulus values in them. I'm not asking for a total explanation, but more of a hint would help.

Thanks,
James
 
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The shear modulus formula will allow you to calculate Poisson's Ratio.

G = E/(2*(1+v))

Where G is the shear modulus, E is the modulus of Elasticity, and v is Poisson's Ratio.

Thanks
Matt
 
Last edited:
Thank you so much! I actually discovered that shortly after I posted the thread.

Thank you again.
James
 

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