Find possible subgroups given some elements

  • Thread starter Thread starter gummz
  • Start date Start date
  • Tags Tags
    Elements
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
4 replies · 4K views
gummz
Messages
32
Reaction score
2

Homework Statement



Suppose that H is a subgroup of Z under addition and that H contains 2^50 and 3^50. What are the possibilities for H?

Homework Equations



Relevant concepts are just the definitions for a group and subgroup.

https://en.wikipedia.org/wiki/Group_(mathematics)

https://en.wikipedia.org/wiki/Subgroup

The Attempt at a Solution



The solution I was given is the following:

V4SNMuS.png


But what I'm wondering about, and would appreciate an answer to, is the following:

But the subgroup has operation "addition" so 2^50 = 50*2 = (2*5*5)*2, and 3^50 = 50*3 = (2*5*5)*3, so the possibilities for H are:

H=Z, H=2Z, H=10Z, H=25Z, H=50Z.

Or am I missing something?
 
Physics news on Phys.org
Thanks for reply. But if we write out the notation, then, for group with operation "addition":

250 = 50*2, and 502=2*50, and Z is commutative? That is, in general, an=n*a
 
gummz said:
Thanks for reply. But if we write out the notation, then, for group with operation "addition":
250 = 50*2

I think the notation used in the problem isn't consistent with the interpretation of ##a^k## for a group element ##a##. You are correct that for a group operation denoted "##*##", the interpretation of the notation ##a^3## is usually ##a*a*a##. So for the operation "##+##", the interpretation would be "##a+a+a##". However, I think the problem is using the notation for exponents in the standard sense that it is used for the field of real numbers. By that notation ## 2^3 = (2)(2)(2)## instead of ##2+2+2##.