Find potential energy using time-independent Schrodinger's equation

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SUMMARY

The discussion centers on determining the potential energy function U(x) using the time-independent Schrödinger equation. The derived expression for U(x) is (2h²/mL⁴)(x² - 3L²/2), which indicates that U(x) is a parabola centered at x = 0 with a minimum value of U(0) = −3h²/mL². The key takeaway is that substituting x = 0 into the equation yields the correct potential energy value, confirming the parabolic nature of U(x).

PREREQUISITES
  • Understanding of the time-independent Schrödinger equation
  • Familiarity with potential energy functions in quantum mechanics
  • Basic knowledge of parabolic functions and their properties
  • Proficiency in algebraic manipulation of equations
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  • Study the implications of potential energy shapes in quantum mechanics
  • Learn about the significance of minima and maxima in potential energy graphs
  • Explore the relationship between wave functions and potential energy in quantum systems
  • Investigate the role of boundary conditions in solving the Schrödinger equation
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Students and professionals in physics, particularly those focusing on quantum mechanics, as well as educators seeking to clarify concepts related to potential energy and wave functions.

eloiseh
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Homework Statement
In a region of space, a particle with mass m and with zero energy has a time-independent wave function ψ(x) = Axe^(−x^2/L^2) where A and L are constants.
Determine the potential energy U(x) of the particle.
Relevant Equations
The time-independent Schrodinger's equation
I had found what U(x) was equal to already by plugging in the wave function and simplifying, which is (2h^2/mL^4)(x^2 - 3L^2/2) by the way.

But the solution key that I have goes an extra step. After stating the equation of U(x) that I got, it says that: "U(x) is a parabola centred at x = 0 with U(0) = −3h^2/mL^2"

Does that mean that I have to plug 0 in for x for the right answer? And how to determine that U(x) is a parabola centred at x=0?
 
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eloiseh said:
I had found what U(x) was equal to already by plugging in the wave function and simplifying, which is (2h^2/mL^4)(x^2 - 3L^2/2) by the way.

Does that mean that I have to plug 0 in for x for the right answer? And how to determine that U(x) is a parabola centred at x=0?
Your solution is a parabola centred at ##x=0##.
 
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PeroK said:
Your solution is a parabola centred at ##x=0##.
Thank you so much!
 

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