Find Pressure from Force: Calculate PSI for 400lbs

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SUMMARY

The discussion focuses on calculating pressure in pounds per square inch (psi) generated by a force of 400 lbs in a punching scenario. The formula used is Pressure = Force / Area (P = F/A), where a 1/4 square inch punch results in 1,600 psi. Additionally, the conversation highlights the distinction between static and impact loading, emphasizing that in impact situations, the force is calculated as mass times acceleration (F = ma). This leads to the conclusion that the basic formula remains applicable regardless of the loading type.

PREREQUISITES
  • Understanding of basic physics principles, specifically Newton's laws of motion.
  • Familiarity with pressure calculations and units, particularly psi.
  • Knowledge of surface area measurements in square inches.
  • Concept of static versus dynamic (impact) loading scenarios.
NEXT STEPS
  • Research the effects of impact loading on material deformation.
  • Learn about the relationship between force, mass, and acceleration in various contexts.
  • Explore advanced pressure calculation techniques for different surface areas.
  • Investigate applications of pressure calculations in engineering and material science.
USEFUL FOR

Engineers, physicists, and anyone interested in mechanics, particularly those involved in material testing and impact analysis.

infraray
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If I have something that can lift 400lbs. How would I determine how much pressure this could generate if used in a punch type situation. I would be punching a hole.
 
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If I understand the question correctly, you just divide your 400 lbs. by the surface area over which it is applied. For instance, a 1/4 sq. inch punch with 400 lbs behind it would exert 1,600 psi.
 
Yeah, that was exactly what I was wanting to know. I don't know why I was thinking it was more difficult. Thanks.
 
Quite welcome, I'm sure. :smile:
 
Danger said:
Quite welcome, I'm sure. :smile:


Actually, that depends on the kind of loading (i.e. static or impact).
It is true that to solve for stress, one only needs to divide F/A.
However, in an impact situation, you force is actually mass times acceleration. Therefore,

Stress = ma/A

(I think) :biggrin: :biggrin: :biggrin:
 
The wording of the question sort of led me to think that infraray was considering the use of an arbour press or such-like, so I assumed the impact speed to be negligible. It would be a little more complicated if he were using a gun of some kind, because there'd probably be deformation of the tool head and more heat production. That's a little out of my league.
 
Actually acording to Newtons second law of motion F=ma and their for ma/A=F/A so it does not mater either way
 

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