Find Rate Law Equation from Experimental Data

  • Thread starter Thread starter mohamma1
  • Start date Start date
  • Tags Tags
    Law Rate
Click For Summary

Discussion Overview

The discussion revolves around the determination of rate law equations from experimental data in chemical kinetics, particularly focusing on the relationship between reaction coefficients in rate-determining steps and their corresponding orders in rate laws. Participants explore concepts related to multi-step reactions, the significance of the slow step, and the experimental basis for determining reaction orders.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants propose that the coefficients in front of reactants in a rate law equation do not necessarily correspond to their orders, emphasizing the need for experimental determination.
  • Others argue that in multi-step reactions, the rate-limiting step is crucial for determining the overall rate, suggesting that it can be assumed that the coefficients represent the order of the reactants in that step.
  • A participant expresses confusion about why the coefficient of the slow step is considered the order in the rate equation, seeking clarification on this point.
  • Some contributions discuss the statistical basis for reaction rates, noting that simultaneous collisions of multiple molecules are improbable, leading to the consideration of intermediates in reaction mechanisms.
  • A later reply mentions that while the rate-determining step can be inferred from experimental data, predicting it theoretically is complex and often relies on educated guesses.
  • Participants discuss various experimental techniques for determining reaction orders and the challenges associated with observing reaction mechanisms directly.
  • One participant introduces RRKM theory, suggesting that the order of an unimolecular reaction can vary with the energy available to the molecule.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between coefficients in the rate-determining step and their corresponding orders in the rate law. While some suggest that the coefficients can be assumed to represent the orders, others emphasize the necessity of experimental validation, indicating that the discussion remains unresolved.

Contextual Notes

Participants note that determining the rate-limiting step and the corresponding reaction order is often based on experimental results, but the theoretical prediction of these steps is complex and not straightforward.

mohamma1
Messages
10
Reaction score
0
When determining a rate law equation you find the individual orders via experimental data, thus you don't assume the coefficients in front of the reactants are their order in the rate law equation. aA + bB -> cC | Rate law equation is not necessarily, rate = k[A]^a^b

But how come when given the "slow" step for a multi-step process, I assume the coefficient is the order for the reactant? aA + bB -> cC | Rate law equation is, rate = k[A]^a^b
 
Last edited:
Chemistry news on Phys.org
In a multi-step process, the "rate-liming" (slow) step is the only one that matters (approximately) for determining the overall rate. The slow step creates a bottleneck, the other fast steps either before or after the bottleneck, are having no effect on the overall process.
 
Thanks for the reply. That part I fully understand. But what is confusing me is why the coefficient is the power (or order) the concentration is raised to in the rate equation.
 
Honestly I don't understand what you are asking about. Please try to reword your question.

As far as I can tell order of the slow step is determined experimentally as well.

--
methods
 
mohamma1 said:
Thanks for the reply. That part I fully understand. But what is confusing me is why the coefficient is the power (or order) the concentration is raised to in the rate equation.
Ah, I see, sorry.
When you have a single indivisible reaction it just comes down to statistics.
If your reaction looks like A + 2B --> C, you require the interaction of one A molecule and two B molecules, simultaneously. The probability of that occurring is A times B times B or
<br /> R \propto A\times B^2<br />
 
zhermes said:
If your reaction looks like A + 2B --> C, you require the interaction of one A molecule and two B molecules, simultaneously. The probability of that occurring is A times B times B or
<br /> R \propto A\times B^2<br />

Well, actually it almost never happens that reactions occur that way; it's extremely improbable to have three molecules colliding with each other simultaneously. In such a case, you would typically have some short lived intermediate, so that:
A + B <-> AB
AB + B --> C

If both these are first-order, the rate of formation of AB is proportional to [A] and the rate of formation of C is proportional to [AB], so the overall rate is proportional to [A]^2.
 
Borek said:
Honestly I don't understand what you are asking about. Please try to reword your question.

As far as I can tell order of the slow step is determined experimentally as well.

--
chemical calculators - buffer calculator, concentration calculator
www.titrations.info - all about titration methods


I'm reviewing my old chemistry stuff and the textbooks I read just assumes that the rate law equation is based off of the coefficients of the rate-determining step rather than experimental data.

Example:

2A + 3B > 4C
4C + D > 3E
_______________
2A + 3B + D > 3E

If the rate-determing step is 2A + 3B -> 4C
Then the rate law = kA2B3
 
How do you know what is the rate determining step? From the experiment... so the reaction equation is already based on the experimental results, no wonder it is exact and can be used to calculate the reaction order.

--
 
Borek said:
How do you know what is the rate determining step? From the experiment... so the reaction equation is already based on the experimental results, no wonder it is exact and can be used to calculate the reaction order.
Often you can predict it theoretically. Consider bimolecular and unimolecular nucleophilic substitution reactions in organic chemistry.
 
  • #10
Borek said:
How do you know what is the rate determining step? From the experiment... so the reaction equation is already based on the experimental results, no wonder it is exact and can be used to calculate the reaction order.

--
ChemBuddy chemical calculators - buffer calculator, stoichiometry calculator
www.ph-meter.info - ph meter, ph electrode


Ohhh, you're right. If you know the rate determining step then you have experimental data. So then it is correct to assume the coefficient is the exponent to which the concentration is raised, given it is the rate determining step?
 
  • #11
A little bit convoluted, but sounds about right.

--
 
  • #12
You can't really predict the rate-limiting step theoretically, short of doing an explicit quantum-chemical calculation. In fact, it's difficult to predict any of the steps. Most of the time you're doing educated guesses based on chemical intuition and similar known mechanisms. Determining the reaction order is relatively simple to do experimentally (plot concentrations versus time basically), and also the transition state energy (same experiment, but vary the temperature so you can determine dS). Depending on your interest, this is often good enough - as one professor told me as an undergrad - it doesn't really matter if you have two or fifty intermediates, if they're not rate-limiting.

On the other hand, if your main interest is in catalysis, and the details of how the reaction occurs, it's tricky. The only way to "directly" observe the reaction is to use ultrafast laser spectroscopy, which is difficult and still a fairly rare procedure. There's a whole host of experimental techniques to try to glean information though, looking for bireactions; reacting with analogues, using isotope labeling of certain atoms to see where they end up, using various reactants and tricks to 'trap' the reaction at some intermediate that you can characterize, looking for kinetic isotope effects (e.g. a deuterium bond will break more slowly than a hydrogen bond since it's heavier and slower), and so on.

Then there's pure theory (what I do), which is to test the plausible mechanisms and use quantum chemical methods to calculate the theoretical transition-state energies for the various methods. QC methods aren't yet accurate enough (in most cases) to correctly predict kinetics, but they're at least accurate enough to give an idea of which mechanisms are more likely and which ones are certainly impossible.
 
  • #13
I wanted to mention RRKM theory (Rice Ramsberger Kassel Marcus) which explains that even the order of an unimolecular reaction can change with the energy available to the molecule.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
8K
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
10K
Replies
9
Views
28K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
3
Views
3K
  • · Replies 16 ·
Replies
16
Views
7K
  • · Replies 3 ·
Replies
3
Views
2K