Find Resistivity of Germanium Sample Setup

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Homework Help Overview

The discussion revolves around calculating the resistivity of a germanium sample based on its resistance and dimensions. Participants are exploring the implications of the sample's setup, particularly regarding the placement of contacts at the corners and the resulting mathematical considerations.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to use integrals due to the corner contact setup, questioning the validity of their resistivity equations. There is also exploration of the implications of contact area approaching zero and its effect on resistivity.

Discussion Status

The discussion is ongoing, with participants seeking clarification on their approaches and the setup of integrals. Some have provided hints and asked for more details about the problem context, while others express confusion about the calculations and the relationship between resistance and resistivity.

Contextual Notes

Participants mention specific resistance values measured in a lab setting and the need to reconcile their calculated resistivity with accepted values. There is a call for more complete problem statements to facilitate better understanding.

atwong713
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Homework Statement


calculate the resistivity of the germanium sample
setup below given the resistance and the dimensions
http://img25.imagevenue.com/img.php?image=91205_lab5_122_1170lo.JPG

Homework Equations


Resistivity=(resistance*Length)/(Area)

The Attempt at a Solution


Ok so I know how to find the resistivity of the setup if the wires were not on the corners of the sample, but since it is on the corner i know that i have to use an integral, so i have to use an integral right?

then dResistivity=(Resistance*dx)/A
putting the sample on a coordinate system
and after finding the value of y in terms of x
A = Thickness*(sqrt(50)-2x)
is this right so far??
i tried to do this but i keep getting a resistivity that is off from the resistivity of germanium
 
Last edited:
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And what is the set-up again?
 
What is the minimum contact cross section at the corner?

As that approaches 0, the resistivity approaches infinity doesn't it?
 
LowlyPion said:
What is the minimum contact cross section at the corner?

As that approaches 0, the resistivity approaches infinity doesn't it?

lol what do you mean?
 
atwong713 said:
lol what do you mean?

Resistivity=(resistance*Length)/(Area)

When area approaches 0 ...
 
ok so there is an infinite resistivity when the area approaches zero do you have any hints on what to do next and how to set up the integral...I'm still kind of lost...do i integrate this from the middle of the square to the corner because of symmetry?
 
atwong713 said:
ok so there is an infinite resistivity when the area approaches zero do you have any hints on what to do next and how to set up the integral...I'm still kind of lost...do i integrate this from the middle of the square to the corner because of symmetry?

Are you sure your equation for resistivity is correct is my point.

http://en.wikipedia.org/wiki/Resistivity
 
LowlyPion said:
Are you sure your equation for resistivity is correct is my point.

http://en.wikipedia.org/wiki/Resistivity

ooo whoops i wrote the equation down wrong
i was suppose to do
dR=(resistivity*dx)/A
then integrate right? or do i use
dResistivity=(Resistance*A)/dx?

ok so i did it with the
dR=(resistivity*dx)/A
but i got ln(0) so it approaches -inf??
 
Last edited:
What is it you are trying to calculate?

The resistivity?

Or the resistance?

Your original post says resistivity.
 
  • #10
LowlyPion said:
What is it you are trying to calculate?

The resistivity?

Or the resistance?

Your original post says resistivity.

im given the resistance of 2755Ohms at 300K
and I'm trying to find the resistivity.
so I'm guessing since i have the resistance i integrate all the resistances since they are in series so they just add?

this is what I've done so far
http://img226.imagevenue.com/img.php?image=91044_lab51_122_395lo.jpg
 
Last edited:
  • #11
atwong713 said:
im given the resistance of 2755Ohms at 300K
and I'm trying to find the resistivity.

Where did this come from?

Maybe if you gave a complete statement of the problem it would be a little easier?
 
  • #12
o I'm sorry i shouldve been more specific i actually measured this in a lab and this is one of the questions for my lab report
so i measured the resistance of the germanium at different temperatures and now I'm just trying to find the resistivity given the setup i posted ealier
the dimensions of the sample is also on my first post...the only problem now is that I'm not sure how to setup the integral for finding this resistivity
 
  • #13
ok for my end result i calculated a resistivity of .256(Ohm meters) using a resistance of 2755Ohms but the accepted value is .46 so am i doing this correct?
 

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