In a potentiometer 99cm of wire of resistance 99ohms is connected with a battery of 50V and 1ohm internal resistance.Find emf of battery giving zero deflection for a length of 13cm.
Sadly,the formula I know is only for ideal emfs,which states that:
If two batteries with emf E1 and E2 obtain null point at L1 and L2 lengths of the potentiometer wire respectively,then : E1/E2=L1/L2
The Attempt at a Solution
The question doesn't mention connecting 2 emfs,just 1 case,1setup,hence the formula I know can't be used here.
A potentiometer is supposed to compare emfs based on where their null points are obtained,right?Then,how am I supposed to find the emf with just 1 setup(that too batteries with internal resistance)?
(Maybe I misunderstood the language of the question.Any other interpretations would be useful)