Find Resultant Force of F1,3 & F2,3 | .899 N Magnitude

Click For Summary
SUMMARY

The resultant force for the two forces F1,3 and F2,3, both with a magnitude of 0.899 N, can be calculated by adding their respective components. F1,3 has components of x = -0.719 and y = -0.54, while F2,3 has components of x = 0.719 and y = -0.54. The resultant force's x-component is the sum of the x-components, resulting in 0, and the y-component remains -0.54. Therefore, the resultant force is 0 N in the x-direction and -0.54 N in the y-direction.

PREREQUISITES
  • Understanding of vector addition
  • Knowledge of force components in physics
  • Familiarity with trigonometric functions
  • Basic knowledge of Newton's laws of motion
NEXT STEPS
  • Study vector addition techniques in physics
  • Learn about force decomposition and its applications
  • Explore trigonometric functions related to angles and forces
  • Investigate Newton's laws of motion for practical applications
USEFUL FOR

Students in physics, engineers working with forces, and anyone studying vector mechanics will benefit from this discussion.

physicshelp45
Messages
1
Reaction score
0
I need to find the resultant force for two separate forces - F1,3 and F2,3. F1,3's components are x= -.719 and y= -.54. F2,3's components are x= .719 and y= -.54. The angle between the q1-q3 line and the x-axis is 36.9. F1,3 and F2,3's magnitude is .899 N. Can someone help me?
 
Physics news on Phys.org
Just add the components.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
6K
Replies
3
Views
2K
Replies
8
Views
4K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
4
Views
911
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K