The problemFind side length using trig

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To find the length of side BC in the triangle with given dimensions, the sine law and cosine law are suggested as useful approaches. The triangle is divided into two right triangles at point D, with side lengths calculated using the ratios of a 30-60-90 triangle and a 45-45-90 triangle. The calculations reveal that BD is 10 cm, but confusion arises regarding the correct application of trigonometric ratios for both triangles. Clarification is also provided on the use of dollar signs for LaTeX formatting in mathematical expressions. The discussion emphasizes the need for accurate application of trigonometric principles to determine the hypotenuse BC.
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Homework Statement



$AB = 20 cm$, $m∠A = 30°$ , and $m∠C = 45°$ . Express the number of centimeters in the length of $BC$ in simplest radical form.

Homework Equations


$sin A = sin C$

The Attempt at a Solution


$AB = 20, BC = x$

D is the point where this obtuse triangle separates into 2 right triangles

$BD/20 = sin A$
$AD/20 = cos A$

30-60-90 triangle
$1:2:\sqrt{3}$

BD is 10 according to this ratio which means that sin A is 1/2 and AD would be $20\sqrt{3}$

sin C is the same but for a 45-45-90 triangle instead.

45-45-90 triangle
$1:1:\sqrt{2}$

But here is where I am stuck. I am trying to find the side lengths of the 45-45-90 triangle with the trigonometric ratios being the same for both triangles but the angles being different so that I know the hypotenuse BC. But I don't know what side lengths will give me the trigonometric ratios being the same and the $1:2:\sqrt{3}$ and $1:1:\sqrt{2}$ side length ratios being true.
 
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caters said:

Homework Statement



$AB = 20 cm$, $m∠A = 30°$ , and $m∠C = 45°$ . Express the number of centimeters in the length of $BC$ in simplest radical form.

Homework Equations


$sin A = sin C$

The Attempt at a Solution


$AB = 20, BC = x$

D is the point where this obtuse triangle separates into 2 right triangles

$BD/20 = sin A$
$AD/20 = cos A$

30-60-90 triangle
$1:2:\sqrt{3}$

BD is 10 according to this ratio which means that sin A is 1/2 and AD would be $20\sqrt{3}$

sin C is the same but for a 45-45-90 triangle instead.

45-45-90 triangle
$1:1:\sqrt{2}$

But here is where I am stuck. I am trying to find the side lengths of the 45-45-90 triangle with the trigonometric ratios being the same for both triangles but the angles being different so that I know the hypotenuse BC. But I don't know what side lengths will give me the trigonometric ratios being the same and the $1:2:\sqrt{3}$ and $1:1:\sqrt{2}$ side length ratios being true.
Your result for the length of side AD is incorrect.
 
I second what SammyS says.
Once you know BD though, you should quickly know BC, since BC is the hypotenuse of the 45-45-90 triangle, right? You have already written the appropriate ratio for the length of a side to the hypotenuse of this triangle.
 
caters said:

Homework Statement



$AB = 20 cm$, $m∠A = 30°$ , and $m∠C = 45°$ . Express the number of centimeters in the length of $BC$ in simplest radical form.

Homework Equations


$sin A = sin C$
No, with A= 30 degrees and B= 45 degrees sin(A) is definitely not equal to sin(C)!
Perhaps you meant the sine law:
\frac{sin(A)}{BC}= \frac{sin(B)}{AC}= \frac{sin(C)}{AB}
The cosine law might also be useful:
(AB)^2= (AC)^2+ (BC)^2- 2(AC)(BC) cos(C)
and equivalent formulas for the other two angles.

3. The Attempt at a Solution
$AB = 20, BC = x$

D is the point where this obtuse triangle separates into 2 right triangles

$BD/20 = sin A$
$AD/20 = cos A$

30-60-90 triangle
$1:2:\sqrt{3}$

BD is 10 according to this ratio which means that sin A is 1/2 and AD would be $20\sqrt{3}$

sin C is the same but for a 45-45-90 triangle instead.

45-45-90 triangle
$1:1:\sqrt{2}$

But here is where I am stuck. I am trying to find the side lengths of the 45-45-90 triangle with the trigonometric ratios being the same for both triangles but the angles being different so that I know the hypotenuse BC. But I don't know what side lengths will give me the trigonometric ratios being the same and the $1:2:\sqrt{3}$ and $1:1:\sqrt{2}$ side length ratios being true.
 
I'm kind of new here... can someone please tell me what the dollar signs represent?
 
Saracen Rue said:
I'm kind of new here... can someone please tell me what the dollar signs represent?

They should be double dollar signs, and they're just a simpler alternative to the tags.
 
Saracen Rue said:
I'm kind of new here... can someone please tell me what the dollar signs represent?
To further explain:

The dollar signs (as well as the # sign ) are used as tags to enable using "LaTeX" for displaying mathematical expressions.

On this site, those should be doubled.

For instance, $20\sqrt{3}$ , should have been ## $ \$ 20\text{\sqrt } 3 ## ## $$ ## .

It would display $$20\sqrt{3}$$
 
Last edited:

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