- #1

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- Homework Statement
- see attached

- Relevant Equations
- Trigonometry

I was just checking this out the sin##\frac {A}{2}## property, in doing so i picked a Right-Angled triangle, say ##ABC##, with ##AB=5cm##, ##BC=4cm## and ##CA= 3cm##. From this i have,

##s=6cm## now substituting this into the formula,

##sin\frac {A}{2}##= ##\frac {1×3}{5×3}##=##\frac {3}{15}##=##0.2##

giving us angle ##A=23.06^0## which does not look correct to me because,

angle ##A=53.13^0## ...using trigonometry directly...##sin{A}##= ##\frac {4}{5} =0.8##... i suspect a mix up in the indicated property...or i may have made a mistake.

i will amend my latex later using phone...

aaaaaaaaargh these guys are missing the square root sign! I had to check that from google.

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