MHB How Do You Calculate the Slant Height of a Cone?

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To calculate the slant height of a cone, use the formula for total surface area: A_T = πr s + πr², where A_T is the total surface area, r is the radius, and s is the slant height. For a cone with a total surface area of 300π cm² and a radius of 10 cm, rearranging the formula gives s = (A_T - πr²) / (πr). In the second scenario, with a slant height of 20 cm and a curved surface area of 330 cm², the radius can be found using A_L = πr s, leading to r = A_L / (πs). Finally, the circumference of the base can be calculated using the formula C = 2πr.
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Hello,

Could anyone help me understand the steps on the below questions?

A cone has a total surface area of 300π cm² and a radius of 10 cm. What is its slant height?


A cone has a slant height of 20 cm and a curved surface area of 330 cm2. What is the circumference of its base? I'd really like to know what steps I need to take to get to the answer on these.

Thank you in advance :-)
 
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gazparkin said:
Hello,

Could anyone help me understand the steps on the below questions?

A cone has a total surface area of 300π cm² and a radius of 10 cm. What is its slant height?


A cone has a slant height of 20 cm and a curved surface area of 330 cm2. What is the circumference of its base? I'd really like to know what steps I need to take to get to the answer on these.

(1) total surface area = lateral surface area + base area

$A_T = \pi r s + \pi r^2$, where $s$ is the slant height and $r$ is the base radius

solving for $s$ $\implies s = \dfrac{A_T - \pi r^2}{\pi r}$

(2) assuming "curved surface area" is the lateral surface area ...

$A_L = \pi r s \implies r = \dfrac{A_L}{\pi s}$

use the formula for a circle's circumference to finish
 
Suppose a cone (minus the circular bottom) has radius r and slant height s. Cut a slit along the slant and flatten it (Unlike a sphere a cone can be flattened. it is a "developable surface."). It will form part of a circle with radius h. That entire circle has radius h so area \pi h^2 and circumference 2\pi h. But the base of the cone had radius r so circumference 2\pi r. The cone is only \frac{2\pi r}{2\pi h}= \frac{r}{h} of the entire circle so has area \frac{r}{h}\pi h^2= \pi rh.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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