Find tension in cables with forces acting on them.

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SUMMARY

The discussion focuses on calculating the tension in cable members AC and BC in a pulley system subjected to a 300 N weight force. The user determined the total horizontal force at point C to be 289.778 N and the total vertical force at point C to be 77.646 N. The user initially attempted to halve the horizontal force to find the tension in each cable but expressed uncertainty about the validity of this approach. The solution requires applying static equilibrium principles and trigonometric functions to accurately resolve the forces in the cables.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Knowledge of trigonometric functions (sine, cosine, tangent)
  • Familiarity with force analysis in pulley systems
  • Basic mechanics concepts (Newton's laws of motion)
NEXT STEPS
  • Study static equilibrium in two-dimensional systems
  • Learn how to apply trigonometric functions in force resolution
  • Explore examples of pulley systems in mechanics textbooks
  • Practice problems involving tension in cables with varying weights
USEFUL FOR

Students in engineering mechanics, physics enthusiasts, and anyone studying tension forces in pulley systems.

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Homework Statement



LOOK AT ATTACHED IMAGE FOR DIAGRAM OF QUESTION

Assuming the pulley at D to be frictionless, determine the force values in cable members AC and BC due to the 300 N weight force for the system depicted in Fig. 3.


Homework Equations



F=ma (or F=mg)
Sin cos and tan functions

Not sure what else would be relevant here.


The Attempt at a Solution



I made the tension of the wire with the weight attached to be 300N (the force of the weight). From this i found:

Total horizontal force at C = 289.778N
Total vertical force at C = 77.646N

At first I thought that if i halved the horizontal force (289.778/2 = 144.889) then I could use that to find each section separately, but I have a gut feeling that it won't work that way... Help??
 
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