Find Tension in String: Friction & Pulley

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Homework Help Overview

The problem involves a system of two blocks connected by a string over a pulley, with one block hanging and the other sliding on a table. The context includes considerations of mass, gravitational force, and friction.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of tension in the string, with one suggesting a specific numerical answer. Questions arise regarding the assumptions about the motion of the blocks, particularly whether the block on the table is sliding or at rest. There are mentions of using free body diagrams to analyze the forces and determine acceleration.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem setup. Some guidance has been offered regarding the importance of free body diagrams and the relationship between the blocks' accelerations. There is no explicit consensus on the solution yet.

Contextual Notes

Participants are considering the effects of friction and the conditions of motion for both blocks, with specific values provided for mass and friction coefficient. There is an emphasis on ensuring correct assumptions about the system's behavior.

lostfan176
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An 8.0-kg hanging block is connected by a string over a pulley to a 6.5-kg block sliding on a flat table. If the coefficient of sliding friction is 0.28, find the tension in the string.

is the answer 41.02 N ?
 
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How did you work it out?
 
((8*9.8)/2)+(6.5*.28)
 
so, we assume that the 6.5 block is sliding? not at rest?
 
aq1q said:
so, we assume that the 6.5 block is sliding? not at rest?


i guess so
 
well, draw the free body diagrams..and find what the acceleration is. Since they are both connected by a string, they will accelerate (different directions) with the same magnitudes.
 
getting the free body diagram correct is essential
 
well i am getting an answer in the 40s, i don't want to say the answer.. anyway i got to go.
 

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