Find Tension of the rotating rod at a distance x

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SUMMARY

The discussion focuses on calculating the tension in a rotating homogeneous rod of length L and mass M, rotating with an angular velocity ω. The derived formula for tension at a distance x from the axis of rotation is T(x) = (M/2L)ω²(L² - x²). The solution involves integrating the differential tension equation and confirms that T(L) equals zero, validating the boundary condition. The mathematical steps presented are correct and provide a clear understanding of the tension distribution along the rod.

PREREQUISITES
  • Understanding of rotational dynamics and angular velocity
  • Familiarity with calculus, specifically integration techniques
  • Knowledge of tension forces in physics
  • Basic principles of homogeneous materials and mass distribution
NEXT STEPS
  • Study the principles of rotational dynamics in greater detail
  • Learn about tension distribution in non-uniform rods
  • Explore advanced integration techniques in calculus
  • Investigate applications of tension in engineering structures
USEFUL FOR

This discussion is beneficial for physics students, mechanical engineers, and anyone interested in understanding the mechanics of rotating bodies and tension analysis in materials.

Tanya Sharma
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Homework Statement



A homogeneous rod with a length L and a mass M rotates with an angular velocity ω in a horizontal plane around an axis passing through its end.Find the tension of the rod at a distance x from its axis of rotation .

Homework Equations


The Attempt at a Solution



T(x)-T(x+dx)=\frac{M}{L}ω^2xdx
-dT=\frac{M}{L}ω^2xdx
\int_{T(0)}^{T(x)}dT=-\int_{0}^{x}\frac{M}{L}ω^2xdx
T(x)-T(0)=-\left[\frac{M}{2L}ω^2x^2\right]_{0}^{x}

Now when x=L,T(L)=0

Thus,T(0)=\frac{M}{2L}ω^2L^2

Hence, T(x)=\frac{M}{2L}ω^2(L^2-x^2)

Kindly check the work if mathematically the steps are correct...
 
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It looks good.

ehild
 
ehild...Thank you very much
 

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