# Find the Angular Acceleration with and Without the disk inertia

1. Apr 25, 2013

### Northbysouth

1. The problem statement, all variables and given/known data
Determine the angular acceleration of the uniform disk if (a) the rotational inertia of the disk is ignored and (b) the inertia of the disk is considered. The system is released from rest, the cord does not slip on the disk, and bearing friction at O may be neglected. The angular acceleration is positive if counterclockwise, negative if clockwise.

I have attached an image of the question

2. Relevant equations

3. The attempt at a solution

m1 = 1.5 kg
m2 = 3.1kg
r = 0.32m

I started by summing the moments about O

ƩMO = (-m1gr + m2gr)/IO

IO = 2mr2 but I'm not sure why this is the case. A classmate of mine said something about adding in the inertias from the weight but I'm not sure what this means.

Also, how to I account for the disk inertia?

Any advice would be appreciated.

#### Attached Files:

• ###### dyn 6.048.png
File size:
27.6 KB
Views:
211
2. Apr 26, 2013

### Simon Bridge

... which confused you.

The force on the disk comes from the tensions acting at opposite points.
The tensions come from the weights. The equation is ƩM = Iα ... which is not the same as:
Breaking it down:

In the first case you would be better to find the linear acceleration of the weights, and use that to deduce the angular acceleration of the disk.

In the second case, you have three free-body diagrams instead of just two.
You need ƩF=ma as well as ƩM = Iα