Find the average force exerted on Superman's chest

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SUMMARY

The discussion centers on calculating the average force exerted on Superman's chest when he is hit by bullets during an elastic collision. The scenario involves 149 bullets, each weighing 8.0 grams and traveling at a velocity of 430 m/s. The average force can be determined by considering the conservation of momentum, as the bullets bounce back after colliding with Superman's chest. The correct approach involves calculating the change in momentum of the bullets and applying it over the time interval of 60 seconds.

PREREQUISITES
  • Understanding of elastic collisions and momentum conservation
  • Basic knowledge of physics equations related to force and momentum
  • Familiarity with vector quantities and their implications in physics
  • Ability to perform unit conversions (e.g., grams to kilograms)
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  • Study the principles of elastic and inelastic collisions in physics
  • Learn how to calculate momentum and force using the formula F = Δp/Δt
  • Explore vector quantities and their significance in collision scenarios
  • Practice problems involving conservation of momentum in various contexts
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LesVampires
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Superman leaps in front of Lois Lane to save her from a volley of bullets. In a 1 minute interval, an automatic weapon fires 149 bullets, each of mass 8.0 g, at 430 m/s. The bullets strike his mighty chest, which has an area of 0.74 m2. Find the average force exerted on Superman's chest if the bullets bounce back after an elastic, head-on collision.


i don't c what the area has to do with it i tried multiplyin

number of bullets x mass in kg x velocity / by the time in seconds 60
 
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Almost! That is the force if the collisions were purely inelastic (i.e., if the bullets stuck to Superman). These are elastic collisions.
 
then what would it be? the equation can't figure it out
 
What happens in an elastic collision?
 
well the v is halved right? so 1/2 mv2
 
No. What happens in an elastic collision?
 
momentum is conserved? like KE0=KEf
 
You are having conceptual issues, so please take this one step at a time. What happens in an elastic collision?
 
im honestly clueless at this point... energy is conserved?
 
  • #10
What happens to the bullets? What is their velocity (NOT SPEED) before and after the collision?
 
  • #11
oh its in the opposite direction
 
  • #12
OK. So how much has the momentum changed? Remember that momentum, like velocity, is a vector quantity.
 
  • #13
twice as much?
 
  • #14
That's right. I don't like the question mark, however. It means you are guessing.
 
  • #15
no I am not, coz it acts like distance vs displacement kinda, so i still don't get what's wrong with the equation
 
  • #16
Spell things out then. Draw pictures. Momentum is conserved here, so the momentum changes incurred the bullets also happen to Superman (but in exactly the opposite sense, of course). So what exactly happens to each bullet? Be specific. Don't say "twice as much". (Twice as much as what?)

I have an early meeting tomorrow so I need to go to bed. Good luck!
 
  • #17
never mind i got it!
 

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