Find the average force exerted on Superman's chest

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Homework Help Overview

The problem involves calculating the average force exerted on Superman's chest when bullets collide with him during an attempted rescue. The context includes concepts from mechanics, specifically elastic collisions and momentum conservation.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of elastic versus inelastic collisions, questioning the role of momentum and energy conservation. There are attempts to derive the average force using different approaches, with some participants expressing confusion about the correct application of formulas.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of elastic collisions and their effects on momentum. Some guidance has been offered regarding the nature of momentum changes, but no consensus has been reached on the final calculation.

Contextual Notes

Participants are grappling with the definitions and implications of elastic collisions, particularly how they affect the momentum of the bullets and Superman. There is a noted lack of clarity regarding the application of equations in this context.

LesVampires
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Superman leaps in front of Lois Lane to save her from a volley of bullets. In a 1 minute interval, an automatic weapon fires 149 bullets, each of mass 8.0 g, at 430 m/s. The bullets strike his mighty chest, which has an area of 0.74 m2. Find the average force exerted on Superman's chest if the bullets bounce back after an elastic, head-on collision.


i don't c what the area has to do with it i tried multiplyin

number of bullets x mass in kg x velocity / by the time in seconds 60
 
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Almost! That is the force if the collisions were purely inelastic (i.e., if the bullets stuck to Superman). These are elastic collisions.
 
then what would it be? the equation can't figure it out
 
What happens in an elastic collision?
 
well the v is halved right? so 1/2 mv2
 
No. What happens in an elastic collision?
 
momentum is conserved? like KE0=KEf
 
You are having conceptual issues, so please take this one step at a time. What happens in an elastic collision?
 
im honestly clueless at this point... energy is conserved?
 
  • #10
What happens to the bullets? What is their velocity (NOT SPEED) before and after the collision?
 
  • #11
oh its in the opposite direction
 
  • #12
OK. So how much has the momentum changed? Remember that momentum, like velocity, is a vector quantity.
 
  • #13
twice as much?
 
  • #14
That's right. I don't like the question mark, however. It means you are guessing.
 
  • #15
no I am not, coz it acts like distance vs displacement kinda, so i still don't get what's wrong with the equation
 
  • #16
Spell things out then. Draw pictures. Momentum is conserved here, so the momentum changes incurred the bullets also happen to Superman (but in exactly the opposite sense, of course). So what exactly happens to each bullet? Be specific. Don't say "twice as much". (Twice as much as what?)

I have an early meeting tomorrow so I need to go to bed. Good luck!
 
  • #17
never mind i got it!
 

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