Find the change in electric potential energy

  • Thread starter Octoshark
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  • #1
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Homework Statement



A uniform electric field with a magnitude of 6890 N/C points in the positive x-direction. Find the change in electric potential energy when a +12.5 µC charge is moved 5.87 cm in the following directions.

In the positive x-direction
In the negative x-direction

Homework Equations



U = qEd, right?

The Attempt at a Solution



U = (12.5 x10^-6)(6890)(0.00587) = .00050555 J or .50555 mJ

But that isn't correct, please help ;)
 

Answers and Replies

  • #2
rl.bhat
Homework Helper
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Check the d value.
 
  • #3
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Whoops, thank you. I accidentally had millimeters

Got the right answer now ;)
 

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