Find the change in electric potential energy

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SUMMARY

The discussion centers on calculating the change in electric potential energy when a +12.5 µC charge is moved in a uniform electric field of 6890 N/C. The correct formula used is U = qEd, where q is the charge, E is the electric field strength, and d is the distance moved. The initial calculation mistakenly used millimeters instead of centimeters for the distance, leading to an incorrect result. After correcting the distance to 5.87 cm, the accurate change in electric potential energy is determined to be 0.00050555 J or 0.50555 mJ.

PREREQUISITES
  • Understanding of electric fields and their properties
  • Familiarity with the formula for electric potential energy (U = qEd)
  • Basic knowledge of unit conversions, particularly between centimeters and millimeters
  • Experience with calculations involving microcoulombs (µC)
NEXT STEPS
  • Review the concept of electric potential energy in different contexts
  • Learn about the implications of electric fields in circuit design
  • Explore unit conversion techniques for electrical measurements
  • Investigate the effects of varying charge magnitudes on potential energy
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism, as well as educators and tutors looking for practical examples of electric potential energy calculations.

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Homework Statement



A uniform electric field with a magnitude of 6890 N/C points in the positive x-direction. Find the change in electric potential energy when a +12.5 µC charge is moved 5.87 cm in the following directions.

In the positive x-direction
In the negative x-direction

Homework Equations



U = qEd, right?

The Attempt at a Solution



U = (12.5 x10^-6)(6890)(0.00587) = .00050555 J or .50555 mJ

But that isn't correct, please help ;)
 
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Check the d value.
 
Whoops, thank you. I accidentally had millimeters

Got the right answer now ;)
 

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