Find the critical points of this function:

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SUMMARY

The discussion focuses on finding the critical points of the function f = (1/x) + (1/y) + xy. The critical points are determined by partially differentiating the function with respect to x and y, resulting in the equations -1/x² + y = 0 and -1/y² + x = 0. The stationary point exists at (1/y², 1/x²), but further simplification is necessary to find definitive coordinates. The discussion emphasizes the need to solve the equations y = 1/x² and x = 1/y² simultaneously to identify the nature of the critical points.

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Homework Statement



Find the critical points of this function and determine wether they are local maxima, minima or saddle points...

f=\frac{1}{x} + \frac{1}{y} + xy


The Attempt at a Solution



start off by partially differentiating and setting to zero for x and y:

\frac{\partial f}{\partial x}=\frac{\partial f}{\partial y}=0


\frac{\partial f}{\partial x}= -\frac{1}{x^2} + y = 0

\therefore y=\frac{1}{x^2}


\frac{\partial f}{\partial y}= -\frac{1}{y^2} + x = 0

\therefore x=\frac{1}{y^2}

so:

\exists a stationary point at (\frac{1}{y^2},\frac{1}{x^2})

using D = f_{xx}f_{yy} - (f_{xy})^2




Does all of this look ok so far? because i do not get a definitive answer for where the critical point lies or any indication of it's nature.
 
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No, both conditions have to be satisfied. Surely you can't leave your coordinates in terms of each other - they can and should then be simplified! So, it is a matter of solving the equations
y=\frac{1}{x^2}
x=\frac{1}{y^2}
simultaneously.
 

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