Find the direction and magnitude of the third force

[dg_5021]

Can someone help me with this problem am clueless.

An object acted on by three forces moves with constant velocity. One force acting on the object is in the positive x direction and has a magnitude of 6.5N; a second force has a magnitude of 4.4N and points in the negative Y direction. Find the direction and magnitude of the third force acting on the object?

 

[Jovaro]

Since the velocity of the object is constant, the resultance of the three forces acting on the object is zero.
If there would be a resulting force there would have been an acceleration. F=m*a remember?

If you make a scetch with a dot representing the object and the 2 known forces as vectors you can see approximately where the third force would be and how big it is.

Hopefully you can calculate it as well with these hints.

 

[dg_5021]

Thanks Jovaro for your help

 

[dg_5021]

so according to my understanding the third force has to be a total of 10.9 N in order for the resulant to be zero?and the direction is y positive and x negative

 

[Jovaro]

Not really, take a look at the drawing. That should make it clear.