Find the distance between and object and its image

  • Thread starter Thread starter caitg
  • Start date Start date
  • Tags Tags
    Image
Click For Summary
SUMMARY

The distance between an object and its image formed by a converging lens with a focal length of 72.4 cm, where the image is 2.54 times larger than the object, can be calculated using the lens formula and magnification equations. The relevant equations include magnification (m = -di/do) and the lens formula (1/di + 1/do = 1/f). By manipulating these equations, one can derive the distances needed to find the separation between the object and the image.

PREREQUISITES
  • Understanding of lens formulas and magnification concepts
  • Familiarity with converging lenses and focal lengths
  • Ability to manipulate algebraic equations
  • Basic knowledge of ray tracing techniques
NEXT STEPS
  • Learn how to apply the lens formula in practical scenarios
  • Study ray tracing methods for visualizing lens behavior
  • Explore real-world applications of converging lenses in optics
  • Investigate the effects of varying focal lengths on image formation
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding the principles of lens mechanics and image formation.

caitg
Messages
1
Reaction score
0

Homework Statement



How far apart are an object and an image formed by a 72.4 cm focal length converging lens if the image is 2.54x larger than the object and is real?
(in cm)


Homework Equations



m=-(di/do)

m=f/(f-do)

(1/di)+(1/do)=(1/f)


The Attempt at a Solution



I've tried manipulating these equations to find the distance, but either I don't come up with a reasonable value or I end up with too many variables.
 
Physics news on Phys.org
Hi caitg, welcome to PF.
Would you please show your work in detail?

ehild
 
caitg said:

Homework Statement



How far apart are an object and an image formed by a 72.4 cm focal length converging lens if the image is 2.54x larger than the object and is real?
(in cm)


Homework Equations



m=-(di/do)

m=f/(f-do)

(1/di)+(1/do)=(1/f)


The Attempt at a Solution



I've tried manipulating these equations to find the distance, but either I don't come up with a reasonable value or I end up with too many variables.

A simple ray trace will give you some guidance.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
19
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K