Find the distance between objects and sound source

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SUMMARY

The discussion focuses on calculating the distances L1 and L2 from a sound source to two microphones positioned at specific coordinates. Given that the microphones are separated by a distance of D = 1.21 m and the speed of sound is 342 m/s, the sound reaches the first microphone 1.67 ms before the second. The user attempts to derive L1 and L2 using the equation x = vΔt, resulting in an extra distance of 0.57114 m. The correct values for L1 and L2 are confirmed as 0.996 m and 1.57 m, respectively, but the user struggles with the algebraic manipulation required to arrive at these results.

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  • Understanding of basic physics concepts such as sound propagation and speed.
  • Familiarity with right triangle properties and Pythagorean theorem.
  • Basic algebra skills for manipulating equations with two unknowns.
  • Knowledge of time conversion from milliseconds to seconds.
NEXT STEPS
  • Review the Pythagorean theorem and its application in solving right triangles.
  • Practice algebraic manipulation techniques for solving equations with multiple variables.
  • Study the principles of sound wave propagation and its mathematical modeling.
  • Explore the relationship between time delays and distance in sound localization problems.
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Students in physics or engineering, educators teaching sound wave concepts, and anyone interested in acoustics and sound localization techniques.

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Homework Statement


One microphone is located at the origin, and a second microphone is located on the +y-axis. The microphones are separated by a distance of D= 1.21m. A source of sound is located on the +x-axis, its distance from microphones 1 and 2 being L1 and L2, respectively. The speed of sound is 342 m/s. The sound reaches microphone 1 first, and then 1.67 ms later it reaches microphone 2. Find the distances (in m) of L1 and L2.

Homework Equations


x=vΔt

The Attempt at a Solution


First I converted 1.67 ms to .00167 s. I know that vΔt=the extra distance sound must travel to reach mic 2 (.57114 m) and I know that the sound source and two lengths create a right triangle, but I am stuck on how to get the length of L1.
 
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You have two unknowns, L1 and L2.

You know that D, L1, and L2 form a right triangle. That will give you one equation with the two unknowns.

You've already found the extra distance, and that tells you something about the relationship between L1 and L2 which you can use to write a second equation in the two unknowns.

You should be able to take it from there with a bit of algebra.
 
Nugatory said:
You've already found the extra distance, and that tells you something about the relationship between L1 and L2 which you can use to write a second equation in the two unknowns.

You should be able to take it from there with a bit of algebra.

I have L1^2 + (1.21)^2 = (L1 + .57114)^2 and I can't seem to move the algebra around to get the right answer for L1.

I know that (from the book) L1= .996m and L2= 1.57m, but I never arrive at the right answer. Am I missing a step or just getting the algebra wrong?
 

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