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 Homework Statement
 The picture shows a block of ##m=2 kg## which moves along a cylinder with constant velocity ##1 \frac{m}{s}## relative to Earth due to the force applied in the photo. The coefficient of dynamic friction between the cylinder and the block is ##0.3## and ##0## between the cylinder and the Earth. Determine the distance with respect to the Earth that the block should move so that it moves ##0.05 m## with respect to the cylinder which was static at first.
 Homework Equations
 Newton's equations
I called the block ##A## and ##B## the cylinder. For ##A##, in the non inertial system I wrote
##x) Fr_d F=0##
##y) RW_1=0##
Where ##Fr_d## is the kinetic friction and ##R## the normal force on ##A##
Then, I know that:
##a_{B/A}=a_Ba_A##
##0=a_B a_A##
##a_A=a_B##
##v_{B/A}=v_Bv_A##
##v_{B/A}=v_B(1;0)##
But if the velocity of ##A## is constant, then it has no acceleration and so ##a_B=0## and then ##x_A=t## so I just have to replace with ##0.05##
##x) Fr_d F=0##
##y) RW_1=0##
Where ##Fr_d## is the kinetic friction and ##R## the normal force on ##A##
Then, I know that:
##a_{B/A}=a_Ba_A##
##0=a_B a_A##
##a_A=a_B##
##v_{B/A}=v_Bv_A##
##v_{B/A}=v_B(1;0)##
But if the velocity of ##A## is constant, then it has no acceleration and so ##a_B=0## and then ##x_A=t## so I just have to replace with ##0.05##
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