Find the distance traveled by the block

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SUMMARY

The discussion focuses on calculating the distance traveled by a block of mass 5 kg on a smooth inclined plane at an angle of 73.74 degrees over a time period of 0.8 seconds. The gravitational force components are analyzed, where mg sin(X) is used to determine the acceleration down the slope, resulting in an acceleration of 9.4 m/s². Using the equation of motion, the distance is calculated as 3.008 meters, confirming the solution's accuracy.

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  • Understanding of basic physics concepts, specifically forces and motion.
  • Familiarity with trigonometric functions, particularly sine and cosine.
  • Knowledge of kinematic equations of motion.
  • Basic understanding of gravitational acceleration (g = 9.8 m/s²).
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  • Study the derivation of kinematic equations for motion on inclined planes.
  • Learn about the effects of friction on inclined plane motion.
  • Explore advanced topics in dynamics, such as Newton's second law in non-horizontal motion.
  • Investigate real-world applications of inclined planes in engineering and physics.
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Students studying physics, particularly those focusing on mechanics, as well as educators and tutors looking for examples of inclined plane problems and solutions.

DeanBH
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Homework Statement


A smooth plane is inclined at 73.74 Degrees to the horizontal a block of mass 5kg is on the slope.

its 73.47 degrees inclined
5kg mass
g = 9.8

Find the distance traveled by the block in 0.8 Seconds



The Attempt at a Solution



i can't quite remember how i find this out.

mgsinX works down the plane
mgcosX works in the direction of graity

its smooth = no friction. i can't remember how i balance the equation to work out acceleration and things that i can put it into an equation of motion to find time
 
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DeanBH said:

Homework Statement


A smooth plane is inclined at 73.74 Degrees to the horizontal a block of mass 5kg is on the slope.

its 73.47 degrees inclined
5kg mass
g = 9.8

Find the distance traveled by the block in 0.8 Seconds



The Attempt at a Solution



i can't quite remember how i find this out.

mgsinX works down the plane
mgcosX works in the direction of graity

its smooth = no friction. i can't remember how i balance the equation to work out acceleration and things that i can put it into an equation of motion to find time


gSinX = A = 9.4

s = ut + 1/2AT^"

s = 0*0.8 + 1/2 * 9.4 * 0.8^2

= 3.008 metres..

right? =)
 
I don't see any errors, good work!
 

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