Find the Driving frequency and phase angle for this R-C phasor problem

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SUMMARY

The discussion focuses on calculating the driving frequency and phase angle for an R-C circuit. The driving frequency was determined to be 862 rad/s, which can be converted to Hz using the equation ω = 2πf. The phase angle, tanϕ, was found to be -1, and the total impedance was calculated as 56.5685 ohms. Participants provided guidance on using phasor diagrams and the relationship between current and voltage in series components.

PREREQUISITES
  • Understanding of R-C circuit theory
  • Familiarity with phasor representation of voltages and currents
  • Knowledge of impedance calculations in AC circuits
  • Proficiency in using trigonometric functions for phase angle determination
NEXT STEPS
  • Learn how to calculate phase angles in R-C circuits using phasor diagrams
  • Study the relationship between angular frequency and driving frequency in AC analysis
  • Explore the implications of impedance on current amplitude in series circuits
  • Investigate the effects of varying driving frequency on phase angle and impedance
USEFUL FOR

Electrical engineers, students studying circuit theory, and anyone working with R-C circuits in AC analysis will benefit from this discussion.

MedEx
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Homework Statement
An alternating emf source with a variable frequency fd is connected in series with a 40.0 Ω resistor and a 29.0 μF capacitor. The emf amplitude is 11.9 V. Consider a phasor diagram for phasor VR (the potential across the resistor) and phasor VC (the potential across the capacitor). (a) At what driving frequency fd do the two phasors have the same length? At that driving frequency, what are (b) the phase angle in degrees, (c) the angular speed at which the phasors rotate, and (d) the current amplitude?
Relevant Equations
ℰ=ℰm*sin(ωdt) ; XC=1/(ωd*C) ; Z=sqrt(R^2+(XL-XC)^2)
i=I*sin(ωdt- ϕ) ; VL= I*XL ; tanϕ= (XL-XC)/R
VR= I*R ; XL=ωd*L
VC=I*XC ; I=ℰ/Z
Using the givens I found ωd=862 rad/s, and with some help I got tanϕ=-1 and Z=56.5685 ohms.
But I can't figure out any of the other variables. I'm not even exactly sure what "driving frequency" is and I can't find an equation for it.
 
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The driving frequency is the frequency of the source signal.
862 radians/sec looks right
 
NascentOxygen said:
The driving frequency is the frequency of the source signal.
Do you know what the equation I would need for that is?
 
MedEx said:
Do you know what the equation I would need for that is?
\omega = 2 \pi f should help you convert from rad/s to Hz. I hope that helps.
 
Master1022 said:
\omega = 2 \pi f should help you convert from rad/s to Hz. I hope that helps.
It does! Thanks. so now i found the frequency and the angular frequency. any word on the phase angle or current amplitude?
 
MedEx said:
It does! Thanks. so now i found the frequency and the angular frequency. any word on the phase angle or current amplitude?
For the phase angle, I am assuming that means the phase angle between the V_r and V_c phasors. In that case, you know that the currents are the same through both components (as they are in series), then you know how to get the phasor voltages for both components (via V = I Z as you wrote above). I would advise that you let current act as the reference phasor- by this I mean the one that we measure everything relative to, so we put it on the positive real axis on our phasor diagram. So for example, we know the impedance of a resistor is R (i.e. it is a real number), thus meaning that voltage will just be a scalar multiple of current that is parallel. What can be said for the capacitor? Also, you might think about whether the answer depends on the driving frequency? (BTW, I have just realized that you have calculated tan(phi), so I am guessing that you have this answer already??)

For the amplitude of the current: can you work out the total impedance? If so, can you use V = I Z to solve for I?

Hope that is of some use. I was trying to give hints that wouldn't completely spoil the problem for you.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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