Find the Driving frequency and phase angle for this R-C phasor problem

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Homework Help Overview

The discussion revolves around an R-C phasor problem, specifically focusing on finding the driving frequency and phase angle. Participants are exploring the relationships between angular frequency, impedance, and phasor voltages in the context of an R-C circuit.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the definition of "driving frequency" and its relationship to angular frequency. There are inquiries about the equations needed to convert between rad/s and Hz, as well as how to determine the phase angle and current amplitude in the circuit.

Discussion Status

Some participants have provided helpful guidance regarding the conversion of angular frequency to frequency and the relationship between current and voltage in the circuit. There is ongoing exploration of the phase angle and current amplitude, with hints offered to assist without providing direct solutions.

Contextual Notes

Participants are working within the constraints of the problem, including the definitions of terms like "driving frequency" and the relationships between circuit components. There is an acknowledgment of the need for further clarification on certain variables and equations.

MedEx
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Homework Statement
An alternating emf source with a variable frequency fd is connected in series with a 40.0 Ω resistor and a 29.0 μF capacitor. The emf amplitude is 11.9 V. Consider a phasor diagram for phasor VR (the potential across the resistor) and phasor VC (the potential across the capacitor). (a) At what driving frequency fd do the two phasors have the same length? At that driving frequency, what are (b) the phase angle in degrees, (c) the angular speed at which the phasors rotate, and (d) the current amplitude?
Relevant Equations
ℰ=ℰm*sin(ωdt) ; XC=1/(ωd*C) ; Z=sqrt(R^2+(XL-XC)^2)
i=I*sin(ωdt- ϕ) ; VL= I*XL ; tanϕ= (XL-XC)/R
VR= I*R ; XL=ωd*L
VC=I*XC ; I=ℰ/Z
Using the givens I found ωd=862 rad/s, and with some help I got tanϕ=-1 and Z=56.5685 ohms.
But I can't figure out any of the other variables. I'm not even exactly sure what "driving frequency" is and I can't find an equation for it.
 
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The driving frequency is the frequency of the source signal.
862 radians/sec looks right
 
NascentOxygen said:
The driving frequency is the frequency of the source signal.
Do you know what the equation I would need for that is?
 
MedEx said:
Do you know what the equation I would need for that is?
\omega = 2 \pi f should help you convert from rad/s to Hz. I hope that helps.
 
Master1022 said:
\omega = 2 \pi f should help you convert from rad/s to Hz. I hope that helps.
It does! Thanks. so now i found the frequency and the angular frequency. any word on the phase angle or current amplitude?
 
MedEx said:
It does! Thanks. so now i found the frequency and the angular frequency. any word on the phase angle or current amplitude?
For the phase angle, I am assuming that means the phase angle between the V_r and V_c phasors. In that case, you know that the currents are the same through both components (as they are in series), then you know how to get the phasor voltages for both components (via V = I Z as you wrote above). I would advise that you let current act as the reference phasor- by this I mean the one that we measure everything relative to, so we put it on the positive real axis on our phasor diagram. So for example, we know the impedance of a resistor is R (i.e. it is a real number), thus meaning that voltage will just be a scalar multiple of current that is parallel. What can be said for the capacitor? Also, you might think about whether the answer depends on the driving frequency? (BTW, I have just realized that you have calculated tan(phi), so I am guessing that you have this answer already??)

For the amplitude of the current: can you work out the total impedance? If so, can you use V = I Z to solve for I?

Hope that is of some use. I was trying to give hints that wouldn't completely spoil the problem for you.
 

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