Find the electrical field of a Spherical Shell

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Homework Help Overview

The problem involves calculating the electric field generated by a thin spherical shell with a specified radius and total charge. The context is within electrostatics, focusing on the behavior of electric fields in relation to charged objects.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for the electric field due to a charged sphere and question the implications of being inside or outside the shell. There is also a consideration of the units of charge provided in the problem.

Discussion Status

Some participants have made attempts to calculate the electric field at specified distances, while others are clarifying the meaning of the charge unit. There is a mix of interpretations regarding the charge's unit and its impact on the calculations.

Contextual Notes

There is uncertainty regarding the interpretation of the charge value given as 32%C, with participants questioning whether it refers to microcoulombs or nanocoulombs. This ambiguity may affect the calculations and understanding of the problem.

RedPhoenix
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Homework Statement



Consider a thin spherical shell of radius 14.0 cm with a
total charge of 32.0 %C distributed uniformly on its
surface. Find the electric field (a) 10.0 cm and (b) 20.0 cm
from the center of the charge distribution.

Homework Equations



img34.gif


The Attempt at a Solution



Stumped...

I figured that the E(r) was the electrical field of the sphere.

I did 9.9E9(32E-9/14^2) (also did it in meters too)

I guess I am just completely lost in this one.
 

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Electric field due to a charged sphere at a distance r is given by
E = (1/4πεo)*Q/r^2
In side the charged sphere, the electric field is ...?
 
I got it.

10cm < 14cm, so its inside, meaning = 0

20cm > 14cm, so ke(q/r^2) = 8.99E9(32E-9/.2^2) = 7192, so now I just have to look over where I messed up on the order of magnitude

7.192 MN/C from the center... is the answer!
 
In the problem, the charge is given as 32%C. What is that? micro or nano?
If it is micro, the answer will be correct. You will get 7.192*10^6N/C or 7.192MN/C.
 

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