Find the equation of hyperbola

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SUMMARY

The discussion focuses on deriving the equation of a hyperbola given the point (2√2, 1) from which tangents are drawn. The tangents intersect the coordinate axes at concyclic points, with one tangent inclined at an angle of tan^{-1}(1/√2) to the transverse axis. The equation of the tangent is expressed as y = mx + √(a²m² - b²), where the condition for tangency is c² = a²m² - b². Participants emphasize the need to utilize the concyclic nature of the points to find the missing parameters for the hyperbola and the circle formed by the intercepts.

PREREQUISITES
  • Understanding of hyperbola equations and properties
  • Familiarity with tangent lines and their equations
  • Knowledge of concyclic points and their geometric implications
  • Basic trigonometry, specifically tangent functions
NEXT STEPS
  • Study the derivation of hyperbola equations from given points and tangents
  • Learn about the properties of concyclic points in geometry
  • Explore the relationship between tangents and their intercepts on coordinate axes
  • Investigate the conditions for tangency in conic sections
USEFUL FOR

Mathematics students, geometry enthusiasts, and anyone involved in conic sections or analytical geometry will benefit from this discussion.

utkarshakash
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Homework Statement


From the point (2√2,1) a pair of tangents are drawn to \dfrac{x^2}{a^2}-\dfrac{y^2}{b^2} = 1, which intersect the coordinate axes in concyclic points . If one of the tangents is inclined at an angle of tan^{-1}\frac{1}{√2} with the transverse axis of the hyperbola , then find the equation of
i) hyperbola ii)circle formed using concyclic points

Homework Equations



The Attempt at a Solution


Equation of tangent
y=mx+\sqrt{a^2m^2-b^2}
where m = tan^{-1}\frac{1}{√2}
Passing it through the given point will give me an equation in a and b. But there are two unknowns.
 
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Condition for tangency is ##c^2=a^2m^2-b^2##. Can you find c?

edit: sorry didn't see that you already did this. I think you have to use the fact that the points are concyclic, or find the equation of the other tangent.
 
Last edited:
MrWarlock616 said:
Condition for tangency is ##c^2=a^2m^2-b^2##. Can you find c?

edit: sorry didn't see that you already did this. I think you have to use the fact that the points are concyclic, or find the equation of the other tangent.

But how?
 
utkarshakash said:
But how?

I think some data might be missing. All I can think of is that the slope of the tangent is -B/A where A and B represent the intercepts of this tangent. A relation between A and B can be found by looking at the circle formed by the points of the intercept, as they are at equal distances from the centre...but the centre is not known too..
 

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