Find the equation of the circle

  • Thread starter Thread starter zorro
  • Start date Start date
  • Tags Tags
    Circle
Click For Summary
SUMMARY

The discussion focuses on finding the equation of a circle that touches both axes and has its center on the line defined by the equation x - 2y = 3. The analysis reveals that the center can be represented in the forms (a, a) and (a, -a), but the constraints of the problem indicate that a circle cannot exist with its center on the given line while also touching both axes. The conclusion emphasizes the need to solve for the line equations y = x and y = -x to determine the valid configurations for the circle.

PREREQUISITES
  • Understanding of circle equations in coordinate geometry
  • Familiarity with linear equations and their graphical representations
  • Knowledge of the properties of tangents and intersections
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the derivation of circle equations from geometric properties
  • Explore the implications of circle tangents to coordinate axes
  • Learn about the intersection of linear equations and their geometric significance
  • Investigate the conditions for circles to exist based on their centers and radii
USEFUL FOR

Students studying coordinate geometry, mathematics educators, and anyone involved in solving geometric problems related to circles and linear equations.

zorro
Messages
1,378
Reaction score
0

Homework Statement


Find the equation of the circle which touches the axes and whose centre lies on the line x-2y=3


Homework Equations





The Attempt at a Solution



The given line passes through 1st, 3rd and 4th quadrants.
So the centre of the circle may lie in any of these i.e. it can be of the form (a,a) (a,-a) (-a,-a).
But my book considers only (a,a) (a,-a) for finding the equation of circles.
 
Physics news on Phys.org


for the line y=x/2-3/2 even though it passes through the first quadrant, it doesn't intersect the line y=x, x>0 so there cannot exist a circle with centre on that line which touches both x and y axes.
 


Thanks a lot!
 


No problem :smile: You don't even have to consider which quadrants the line is in, just start solving for that line and the lines y=x and y=-x.
 

Similar threads

  • · Replies 62 ·
3
Replies
62
Views
10K
  • · Replies 48 ·
2
Replies
48
Views
5K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K