Find the equation of the circle

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Homework Help Overview

The problem involves finding the equation of a circle that touches the axes and has its center on the line defined by the equation x - 2y = 3.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the possible locations of the circle's center based on the given line and its relationship to the axes. There is a mention of different forms for the center of the circle and considerations regarding the quadrants.

Discussion Status

The discussion includes various interpretations of the problem, with some participants questioning the feasibility of a circle existing under the given conditions. Guidance has been offered to focus on solving for the line and its intersections with other relevant lines.

Contextual Notes

There is a mention of constraints regarding the quadrants and the specific lines involved in the problem, as well as the implications of the center's location on the circle's ability to touch both axes.

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Homework Statement


Find the equation of the circle which touches the axes and whose centre lies on the line x-2y=3


Homework Equations





The Attempt at a Solution



The given line passes through 1st, 3rd and 4th quadrants.
So the centre of the circle may lie in any of these i.e. it can be of the form (a,a) (a,-a) (-a,-a).
But my book considers only (a,a) (a,-a) for finding the equation of circles.
 
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for the line [tex]y=x/2-3/2[/tex] even though it passes through the first quadrant, it doesn't intersect the line y=x, x>0 so there cannot exist a circle with centre on that line which touches both x and y axes.
 


Thanks a lot!
 


No problem :smile: You don't even have to consider which quadrants the line is in, just start solving for that line and the lines y=x and y=-x.
 

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