Find the equation of the line tangent to two parabolas

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Homework Help Overview

The problem involves finding the equation of a line that is tangent to two given parabolas: f(x) = x^2 - 2x + 2 and g(x) = -x^2 - 2x - 2. Participants are exploring the relationships between the slopes of the tangent line and the points of tangency on each parabola.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to set the slopes of the tangent lines equal to each other and to express the equations in terms of one variable. Some participants question whether the conditions for the points lying on the respective parabolas have been fully utilized in the original poster's approach.

Discussion Status

The discussion is ongoing, with some participants providing guidance on the importance of ensuring that the points of tangency satisfy the equations of the parabolas. There is a mix of interpretations regarding the setup of the problem, and the original poster has indicated progress after reviewing an external tutorial.

Contextual Notes

There is a mention of the original poster's struggle with limiting variables and simplifying equations, as well as the potential oversight in fully applying the conditions of the problem regarding the points on the parabolas.

flemonster
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Homework Statement


Given the two parabolas: f(x) = x^2 - 2x + 2 and g(x) = -x^2 - 2x - 2. Find the equation of a line that is tangent to both curves.

Homework Equations



The given parabolas, equation for a line y = mx + b, and the derivatives of the two parabolas 2x - 2 and -2x - 2

The Attempt at a Solution



The line tangent to the two parabolas will pass through the points

(x_1 , y_1)

for the parabola f(x) and

(x_2 , y_2)

for the parabola g(x)

so the equations for the two lines will be,

for f' y_1 = (2x_1 - 2)x_1 +b

and

g' y_2 = (-2x_2 - 2)x_2 + b.

Since the slopes of both lines will be the same I thought that setting the two slopes equal might get me started so I wrote

2x_1 - 2 = -2x_2 - 2

which gave me \frac{x_1}{x_2} = -1.

I rearranged the two linear equations and set them equal:

y_1 - (2x_1 - 2)x_1 = y_2 - (-2x_2 - 2)x_2

but that got me absolutely nowhere. I got the whole thing down to

x^2 _1 + x^2 _2 = \frac{y_1 - y_2}{2}

but that doesn't help.

I know I need to limit my variables and try to get the whole thing in terms of one variable but I'm at a loss as to how to make that happen. Every time I substitute and simplify I get either one or negative one which tells me nothing. I can't figure out how relate the equations and simplify. Any help is appreciated.
 
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http://www.math.washington.edu/~aloveles/Math124Fall2012/ConroytangentLines01.pdf

I don't know how to do these problems, but that looks exactly how I would go about it. Sorry I can't give any additional help.
 
You do not appear to have used the fact that the points (x1, y1), (x2, y2) lie on the respective parabolas.
 
haruspex said:
You do not appear to have used the fact that the points (x1, y1), (x2, y2) lie on the respective parabolas.

I'm not sure what you mean. I accounted for them being on different parabolas with the subscripts but is there something in their being on different parabolas that I missed?
 
And I just figured it out. That tutorial from UW did the trick which is kind of funny seeing that's where I did my undergrad. Thanks iRaid!
 
flemonster said:
I'm not sure what you mean.
I mean that e.g. x1, y1 satisfy the equation of the first parabola.
 

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