# Find the equation of the normal to the graph at M(2,1)

1. Jan 14, 2009

### Dell

if:
2x3+8lny+x3ey-16-8e=0

what i did was
dy/dx=$$\dot{y}$$

6x2+8(1/y)$$\dot{y}$$+3x2ey+x3ey$$\dot{y}$$=0

$$\dot{y}$$=-(x2(6+3ey)/(8/y+x3ey)

then to find the incline of the normal, m=-1/$$\dot{y}$$

so at(2,1)

$$\dot{y}$$=-3(2+e)/2(1+e)

m(N)=2(1+e)/3(2+e)

does this seem right??

Y-1=[2(1+e)/3(2+e)]{x-2}

2. Jan 14, 2009

### razored

Yes, it's correct.