Find the equation of the parabola

[rowdy3]

Find the equation of the parabola (in standard form) whose vertex is at the origin, has a vertical axis, and passes through the point (-2,5). Thanks

y = ax^2
sub in the point (-2, 5) and solve for a
5 = a(-2)^2
5 = a(4)
a = 5/4
Final equation is y = (5/4)x^2. Is that right?

 

[Mark44]

Find the equation of the parabola (in standard form) whose vertex is at the origin, has a vertical axis, and passes through the point (-2,5). Thanks

y = ax^2
sub in the point (-2, 5) and solve for a
5 = a(-2)^2
5 = a(4)
a = 5/4
Final equation is y = (5/4)x^2. Is that right?

You can check for yourself. If x = -2, is y = 5? Does it go through the origin?