shamieh
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find the equation of the tangent line.$$y = e^{3x + cos x}$$ @ x = 0
$$
y1 = e^{3(0) + cos(0)} = e^1 = e$$
$$y1 = e$$
$$y = e^{3x+cos x}$$
$$y' = e^{3x + cos x} * (3 - sinx)$$
$$m = 3e$$
$$
y - e = 3e(x - 0) $$
$$
y1 = e^{3(0) + cos(0)} = e^1 = e$$
$$y1 = e$$
$$y = e^{3x+cos x}$$
$$y' = e^{3x + cos x} * (3 - sinx)$$
$$m = 3e$$
$$
y - e = 3e(x - 0) $$