Find the equilibrium position for a -5.0 nC charge.

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Leo34005
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Homework Statement



A charge of 2.9 nC and a charge of 5.8 nC are separated by 40.80 cm. Find the equilibrium position for a -5.0 nC charge.

? cm from the 2.9 nC charge.

Homework Equations



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The Attempt at a Solution



F = 2.9/5.8NC/ 4(40.80)
 
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Hint (1): What must the net force acting on the -5nC charge be in order for it to be in equilibrium?

Hint (2): If a point charge [itex]q[/itex] is placed at a point where the net electric field from all other charges is [itex]\textbf{E}[/itex], what is the force [itex]\textbf{F}[/itex] on [itex]q[/itex]?

Hint (3): What does the superposition principle tell you about finding the net electric field at any point in space due to two point charges?
 
Not sure, mind helping me here?
 
Can i please have an answer so i can check if my answer is wrong or right?
 
Leo34005 said:
Can i please have an answer so i can check if my answer is wrong or right?

No, but if you post your answer we can tell you whether it's right or wrong, and even better, if you show your work and explain your reasoning we can point out the source of any errors you are making.
 
Leo is now on a temporary vacation from the PF because of repeatedly refusing to show work in homework threads.