(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

coal is falling onto a conveyor belt at a rate of 540 tonnes every hour. the belt is moving horizontally at 2.0 ms-1. find the extra force required to maintain the speed of the belt. (1 tonne=1000kg.)

2. Relevant equations

F=m*a

3. The attempt at a solution

i tried to solve by saying that F=m*a. so to find force i would need the accelaration of the belt and multiply it by the mass of the coal. the acceleration is the rate of change of velocity so i would use the 2ms-1 as the final velocity and 0 ms-1 as the annitial subtracting 0 from two leaves 2 ms-1 and i divide by the rate of change of time which is 3600s.this leaves me with an accelaeration of 0.000556 ms/s^2 multiplying this by the mass of the coal 540000kg leaves 300 N. is this right

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# Homework Help: Find the extra force required to maintain the speed of the belt

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