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## Homework Statement

A series of small packages, each with a mass of 4 kg, are discharged from a conveyor belt as shown. Assume that the coefficient of static friction between each package and the conveyor belt is 0.4.

Determine the force exerted by the belt on a package just after it has passed Point

*A*

I attached the picture below

## Homework Equations

F = ma

## The Attempt at a Solution

So I began by drawing a FBD:

-W: Weight pointed downwards

-N: Normal pointed upwards

-f: Friction pointed left

-B: Force from the belt pointed right.

From what I understand, we are trying to solve for B.

Also, it is about to enter a circular region, which makes me think that the net acceleration is -mv^2/r in the y direction and dv/dt in the x direction.

So, I began by solving the forces in the y direction:

-mv^2/r = -W + N

-(4)(1^2)/(0.250) = -(4)(9.81) + N

--> N = 23.24 N

From there, I setup the equation in the x direction:

dv/dt = B - (u)N

dv/dt = B - (0.4)(23.24)

Now the thing is, I assumed that the speed is consistent which would imply B = (0.4)(23.24) = 9.296 N.

However, this answer was wrong, so I am not sure how to approach it from here.

#### Attachments

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