A 2.3kg aluminum pan at 135° is plunged into 3.0kg of water at 15°. The specific heat of aluminum is 900 J/(kg K).
Find the final Celsius temperature of the aluminum and water.
T_f = °Celsius
Find the entropy change of the aluminum pan.
ΔS_Al = J/K
Find the entropy change of the water.
ΔS_H20 = J/K
Find the entropy change in the system of particles consisting of all the particles in the aluminum plus all the particles in the water.
ΔS = J/K
The Attempt at a Solution
So my first couple attempts was that we use the equation Q=mC(T_f-T_i)
other related equations i know is DeltaS=Q/T but, how can i find the temperature final of both Water and aluminum.
I tried setting it up like this
m_water*C_water(T_f-T-i) + m_aluminum*C_aluminum(T_f-T_i) = Q_total
but i don't know how to get anything done from there.
Please help me with the first part and i should be able to most of it done on my own.
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