Find the first five terms of sequence

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To find the first five terms of the sequence defined by a1=7 and an=an-1-4 for n>=2, start with a1=7. The second term is calculated as a2=a1-4, resulting in a2=3. Continuing this pattern, a3= a2-4 gives a3=-1, a4=a3-4 results in a4=-5, and a5=a4-4 yields a5=-9. The first five terms of the sequence are 7, 3, -1, -5, and -9. The discussion emphasizes the importance of using parentheses for clarity in the formula.
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How can we find the first five terms of sequence given below?

a1=7; an=an-1 – 4, n>=2
 
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By pluggin in numbers...

a_1 = 7

a_n = a_(n - 1) - 4, n >= 2 (you really need to use parantheses here).

To find a_2, let n = 2. Then we have:

a_2 = a_(2 - 1) - 4 = a_1 - 4 = 7 - 4 = 3.

You use the same technique to find the rest of the numbers.
 
Thanx

Thanx
 
Originally posted by Muzza
(you really need to use parantheses here).

Or Latex
 
Yeah, I guess that works too. ;)
 

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