Find the flux through a surface S (Electromagnetic Theory)

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Homework Help Overview

The problem involves calculating the electric flux through a circular surface in the x-z plane due to two point charges located on the y-axis. The charges are positioned symmetrically, and the task includes both finding the flux and visualizing the electric field lines using Mathematica for different charge scenarios.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the definition of electric flux and the electric field of point charges. There are attempts to apply the formula for flux, with some questioning the validity of using it in this context. Concerns about the specifics of the charges and their effects on the flux are also raised.

Discussion Status

The discussion is ongoing, with some participants providing insights into the nature of electric fields and flux calculations. There is a mix of attempts to clarify concepts and questions about how to approach the problem, particularly regarding the use of Mathematica.

Contextual Notes

Some participants express uncertainty about the definitions and calculations involved, indicating a need for further exploration of the concepts before arriving at a solution. There is also mention of the requirement to show effort before receiving assistance.

jajay504
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Homework Statement


A point charge q1 is located on the y-axis at r1= a (Y_hat) and another q2 located at the mirror point r2= -a (Y_hat). The charges are not necessarily the same sign or magnitude. Now consider the circular surface S of radius a contained in the x-z plane through the origin. Take the normal vector to this surface to point along the positive y-axis.

a.) Find the flux of the electric field through S.
b.) Use Mathematica to plot the field lines in the y-z plane through the origin for the following three cases: q2=-10q1, q2=q1, and q2=10q1.


Homework Equations



I have no idea how to start this problem or how to plug it into mathematica

The Attempt at a Solution

 
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You need to show some effort at trying to solve the problem yourself before receiving help. This is pretty basic stuff. What's the field of a point charge? What's the definition of flux?
 
Flux= EA cos(theta)= E.A
I got flux = q/4e0

I don't have experience using mathematica at all
 
vela said:
You need to show some effort at trying to solve the problem yourself before receiving help. This is pretty basic stuff. What's the field of a point charge? What's the definition of flux?

Sorry for that. This one. I think I may have over thought it a bit.
 
jajay504 said:
Flux= EA cos(theta)= E.A
That only works for a constant electric field.
I got flux = q/4e0
How did you get this? What's q? The original problem has q1 and q2.
 

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