Find the flux through a surface S (Electromagnetic Theory)

  • Thread starter jajay504
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  • #1
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Homework Statement


A point charge q1 is located on the y-axis at r1= a (Y_hat) and another q2 located at the mirror point r2= -a (Y_hat). The charges are not necessarily the same sign or magnitude. Now consider the circular surface S of radius a contained in the x-z plane through the origin. Take the normal vector to this surface to point along the positive y-axis.

a.) Find the flux of the electric field through S.
b.) Use Mathematica to plot the field lines in the y-z plane through the origin for the following three cases: q2=-10q1, q2=q1, and q2=10q1.


Homework Equations



I have no idea how to start this problem or how to plug it into mathematica

The Attempt at a Solution

 

Answers and Replies

  • #2
vela
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You need to show some effort at trying to solve the problem yourself before receiving help. This is pretty basic stuff. What's the field of a point charge? What's the definition of flux?
 
  • #3
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Flux= EA cos(theta)= E.A
I got flux = q/4e0

I don't have experience using mathematica at all
 
  • #4
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You need to show some effort at trying to solve the problem yourself before receiving help. This is pretty basic stuff. What's the field of a point charge? What's the definition of flux?
Sorry for that. This one. I think I may have over thought it a bit.
 
  • #5
vela
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Flux= EA cos(theta)= E.A
That only works for a constant electric field.
I got flux = q/4e0
How did you get this? What's q? The original problem has q1 and q2.
 

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