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Find the function of the form y = tan kx

  1. May 1, 2012 #1
    1. The problem statement, all variables and given/known data

    Find the function of the form y = tan kx that pass through (290 degrees, -1)


    2. Relevant equations

    y = tan kx

    3. The attempt at a solution

    y = tan kx
    -1 = tan k(290 degrees)
    arctan(-1) = k290 degrees
    -pi/4 = K 290

    I don't know where to go from here, or even if this is right...do I try to convert 290 to a rad approximation?? I'm doing this course online and they give very little explaination...Any help is much appreciated!
    Thanks!
     
    Last edited: May 1, 2012
  2. jcsd
  3. May 1, 2012 #2

    tiny-tim

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    Welcome to PF!

    Hi Lepton_dyson! Welcome to PF! :wink:
    Make up your mind! :rolleyes:

    If you have degrees on the RHS, you must have degrees (-45 of 'em) on the LHS also. :smile:
     
  4. May 1, 2012 #3
    Re: Welcome to PF!

    Thanks for the welcome!
    Then I just multiply them? so -45(290) = -13050?
    y = tan -13050 x -------I just didn't think that looked right.....is it?

    Thanks for the help!
     
  5. May 2, 2012 #4

    tiny-tim

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    divide :wink:

    and conquer! :biggrin:
     
  6. May 2, 2012 #5
    Cool thanks for your help!
     
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