# Find the function of the form y = tan kx

1. May 1, 2012

### Lepton_dyson

1. The problem statement, all variables and given/known data

Find the function of the form y = tan kx that pass through (290 degrees, -1)

2. Relevant equations

y = tan kx

3. The attempt at a solution

y = tan kx
-1 = tan k(290 degrees)
arctan(-1) = k290 degrees
-pi/4 = K 290

I don't know where to go from here, or even if this is right...do I try to convert 290 to a rad approximation?? I'm doing this course online and they give very little explaination...Any help is much appreciated!
Thanks!

Last edited: May 1, 2012
2. May 1, 2012

### tiny-tim

Welcome to PF!

Hi Lepton_dyson! Welcome to PF!

If you have degrees on the RHS, you must have degrees (-45 of 'em) on the LHS also.

3. May 1, 2012

### Lepton_dyson

Re: Welcome to PF!

Thanks for the welcome!
Then I just multiply them? so -45(290) = -13050?
y = tan -13050 x -------I just didn't think that looked right.....is it?

Thanks for the help!

4. May 2, 2012

divide

and conquer!

5. May 2, 2012