Find the function of the form y = tan kx

[Lepton_dyson]

Homework Statement

Find the function of the form y = tan kx that pass through (290 degrees, -1)

Homework Equations

y = tan kx

The Attempt at a Solution

y = tan kx
-1 = tan k(290 degrees)
arctan(-1) = k290 degrees
-pi/4 = K 290

I don't know where to go from here, or even if this is right...do I try to convert 290 to a rad approximation?? I'm doing this course online and they give very little explanation...Any help is much appreciated!
Thanks!

 

[tiny-tim]

Welcome to PF!

Hi Lepton_dyson! Welcome to PF!

arctan(-1) = k290 degrees
-pi/4 = K 290

Make up your mind!

If you have degrees on the RHS, you must have degrees (-45 of 'em) on the LHS also.

 

[Lepton_dyson]

Hi Lepton_dyson! Welcome to PF!


Make up your mind!

If you have degrees on the RHS, you must have degrees (-45 of 'em) on the LHS also.

Thanks for the welcome!
Then I just multiply them? so -45(290) = -13050?
y = tan -13050 x -------I just didn't think that looked right...is it?

Thanks for the help!

 

[tiny-tim]

Then I just multiply them?!

divide

and conquer! ​

 

[Lepton_dyson]

divide

and conquer! ​

Cool thanks for your help!