Understanding the change from cot graph to tan graph

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SUMMARY

The discussion centers on understanding the transformations of the cotangent and tangent functions represented by the equations y = a cot k(x−b) and y = a tan k(x−b). Participants clarify that the parameters a, b, and k correspond to amplitude, horizontal shift, and period, respectively. It is established that amplitude does not apply to the cotangent function, and the period needs to be determined from the graph rather than assumed values. The use of graphing tools is recommended for visualizing these transformations.

PREREQUISITES
  • Understanding of trigonometric functions, specifically cotangent and tangent.
  • Familiarity with function transformations, including amplitude, period, and phase shifts.
  • Experience with graphing tools for visualizing mathematical functions.
  • Knowledge of the unit circle and its application in trigonometry.
NEXT STEPS
  • Explore the properties of the cotangent function and its graph.
  • Learn how to determine the period of trigonometric functions using the coefficient k.
  • Utilize graphing software such as Desmos to visualize transformations of y = cot(x) and y = tan(x).
  • Study the differences between amplitude in sine/cosine functions and its non-application in cotangent/tangent functions.
USEFUL FOR

Students studying trigonometry, educators teaching function transformations, and anyone seeking to deepen their understanding of cotangent and tangent graphs.

Niaboc67
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Homework Statement


ygkRmPW.png


Suppose the function is y = a cot k(x−b)

Then (give exact answers; you can type pi for π):
a =
b =
k =

Suppose the function is y = a tan k(x−b), where b > 0.

Then:
a =
b =
k =

The Attempt at a Solution


Then (give exact answers; you can type pi for π):
a = 4 because this is the amplitude?
b = 2 because this is the period?
k = not sure?

the next section I am at lost at
 
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Niaboc67 said:

Homework Statement


ygkRmPW.png


Suppose the function is y = a cot k(x−b)

Then (give exact answers; you can type pi for π):
a =
b =
k =

Suppose the function is y = a tan k(x−b), where b > 0.

Then:
a =
b =
k =

The Attempt at a Solution


Then (give exact answers; you can type pi for π):
a = 4 because this is the amplitude?
b = 2 because this is the period?
k = not sure?

the next section I am at lost at
Do you know what the graph of y = cot(x) looks like? All of the numbers a, k, and b represent some kind of transformation that has been done to the graph of y = cot(x) to get the one in the drawing. Presumably you have been studying these kinds of transformations already.

Regarding your answers, amplitude doesn't apply in this graph. The period is not 2. You can look at the graph and see what the period is.
 
a will amplify the height of the function, so look for what would normally be 1 and see what it is in the graph-- that should be a.
b is a shift.
And k will change the period.
Play around with these and a plotting tool. They will help you understand the role of these coefficients in other expressions.
 

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