Find the general solution of a differential equation

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SUMMARY

The discussion focuses on finding the general solutions for two differential equations: y'''[x] + 2 y''[x] + 5 y'[x] = 0 and y''[x] + 6 y'[x] + 9 y[x] = 0. The correct approach for the first equation involves solving for y' as a second-order differential equation, leading to a general solution of the form y = f(x) with three integration constants. The participant's confusion regarding the form of the general solution was clarified by Jim, who emphasized that y' should be expressed as a function of x before integrating to find y.

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jimkochanski
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Homework Statement



I was asked to find the general solutions of the two following differential equations:

Q1. y'''[x] + 2 y''[x] + 5 y'[x] = 0

Q2. y''[x] + 6 y'[x] + 9 y[x] = 0

Homework Equations



See above.

The Attempt at a Solution



My answers to both problems were of the form y = f[x].

My professor informed me that the general solution for the differential equation y'''[x] + 2 y''[x] + 5 y'[x] = 0 should not have been of the form y = f[x], but should have been of the form y'[x] = f[x].

Is this conventional?

Would that mean the general solution of αy(5)[x] + βy'''[x] = 0 would be of the form y'''[x] = f[x]?

Thanks for sharing your insight/feedback!

Jim
 
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The first equation does not include y(x), so it can be solved for y' as a second order de (use y'=z(x) and solve for z). After solving for z(x)=y'(x), you need to integral y' to get y. So the general solution is a function y=f(x) which contains three integration constants.

ehild
 

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