Find the gravitational force of the sun on Mercury

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SUMMARY

The gravitational force of the Sun on Mercury can be calculated using the formula FG = G * M_sun * M_mercury / R^2. Given the mass of the Sun (M_sun = 1.98892 x 10^30 kg), the mass of Mercury (M_mercury = 3.3022 x 10^23 kg), and the distance between them (R = 6.863 x 10^10 m), the calculated gravitational force is approximately 9.300 x 10^21 N. However, this value may be incorrect if the distance does not account for the radii of the Sun and Mercury, which should be added to the distance for an accurate calculation.

PREREQUISITES
  • Understanding of Newton's Law of Universal Gravitation
  • Familiarity with gravitational constant (G = 6.67 x 10^-11 N(m/kg)^2)
  • Basic knowledge of mass and distance measurements in physics
  • Ability to perform calculations involving scientific notation
NEXT STEPS
  • Review the derivation and application of Newton's Law of Universal Gravitation
  • Learn about the significance of the gravitational constant in various contexts
  • Investigate the impact of celestial body radii on gravitational force calculations
  • Explore gravitational force calculations for other planets in the solar system
USEFUL FOR

Students studying physics, particularly those focusing on gravitational forces, as well as educators and anyone interested in celestial mechanics and astrophysics.

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Homework Statement


Find the gravitational force of the sun on Mercury
M_sun = 1.98892 x10^30 kg
M_mercury = 3.3022 x10^23 kg
Distance of sun and mercury = R = 6.863 x10^10
G = 6.67 x10^-11


Homework Equations


FG = GMsunMmercury/R^2


The Attempt at a Solution



I simply plugged in the given values (which I found from wolfram alpha) into the formula for F_G and I calculated the answer to be:
9.300 x10^21 N

However, the answer is not correct. If anyone can correct my mistake, that would be greatly appreciated.

Thanks
 
Physics news on Phys.org
Where did you get the distance from mercury to the sun, and is it a measurement from the center of the sun to the center of mercury? If not, you may have to add in the radii of the two.
 

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