Find the height from which the ball was thrown

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Homework Statement


A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 9.00 m/s at an angle of 16.0° below the horizontal. It strikes the ground 5.00 s later. (Ignore air resistance.)
(b) Find the height from which the ball was thrown.

Homework Equations



Y-Yo= Vyot -1/2gt^2

The Attempt at a Solution



Yo= -Vyot +1/2gt^2

Yo= -(9sin16)(5) + 1/2(9.8)(25) = 110m
but the answer is wrong.
 
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xjasonx1 said:

Homework Statement


A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 9.00 m/s at an angle of 16.0° below the horizontal. It strikes the ground 5.00 s later. (Ignore air resistance.)
(b) Find the height from which the ball was thrown.

Homework Equations



Y-Yo= Vyot -1/2gt^2

The Attempt at a Solution



Yo= -Vyot +1/2gt^2

Yo= -(9sin16)(5) + 1/2(9.8)(25) = 110m
Your formula above is incorrect. The ball is tossed out of the window at a downward angle. This means that the vertical component of the velocity is in the same direction as gravity is acting. In your formula, Vy0 is negative, but the gravitational force is positive. You can define which sign corresponds to up or down, but you have to be consistent.
xjasonx1 said:
but the answer is wrong.