Your formula above is incorrect. The ball is tossed out of the window at a downward angle. This means that the vertical component of the velocity is in the same direction as gravity is acting. In your formula, Vy0 is negative, but the gravitational force is positive. You can define which sign corresponds to up or down, but you have to be consistent.xjasonx1 said:Homework Statement
A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 9.00 m/s at an angle of 16.0° below the horizontal. It strikes the ground 5.00 s later. (Ignore air resistance.)
(b) Find the height from which the ball was thrown.
Homework Equations
Y-Yo= Vyot -1/2gt^2
The Attempt at a Solution
Yo= -Vyot +1/2gt^2
Yo= -(9sin16)(5) + 1/2(9.8)(25) = 110m
xjasonx1 said:but the answer is wrong.
To calculate the height from which the ball was thrown, you will need to use the equation h = V2sin2(θ) / 2g, where h is the height, V is the initial velocity of the ball, θ is the angle of projection, and g is the acceleration due to gravity (9.8 m/s2).
To find the height from which the ball was thrown, you will need to know the initial velocity of the ball, the angle at which the ball was thrown, and the acceleration due to gravity.
No, the height from which the ball was thrown cannot be negative. It represents the vertical distance from the ground to the point where the ball was released.
Yes, air resistance can affect the calculation of the height from which the ball was thrown. If there is significant air resistance, it can decrease the vertical velocity of the ball and therefore affect the height calculation.
No, it is not possible to find the height from which the ball was thrown without knowing the initial velocity. The initial velocity is a crucial component in the calculation of the height, and without it, the calculation cannot be accurately completed.