[LENS] Given focal length and height, find object distance

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SUMMARY

The discussion focuses on calculating the object distance in front of a convex mirror, given a focal length of 0.2m and an erect image height that is 25% of the object's height. The magnification (M) is established as 0.25, leading to the relationship M = q/p, where q is the image distance and p is the object distance. By applying the mirror formula 1/p + 1/q = 1/f, participants are guided to consider the signs of the focal length and image distance for accurate calculations.

PREREQUISITES
  • Understanding of convex mirrors and their properties
  • Familiarity with the mirror formula: 1/p + 1/q = 1/f
  • Knowledge of magnification and its calculation: M = Yi/Yo
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation and application of the mirror formula in optics
  • Learn about the characteristics of images formed by convex mirrors
  • Explore practical examples of magnification in real-world scenarios
  • Investigate the impact of varying focal lengths on image formation
USEFUL FOR

Students studying optics, physics educators, and anyone seeking to understand image formation in convex mirrors.

Phil123
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Homework Statement


An object is in front of a convex mirror. We then obtain an erect image whose height is equal to 25% of the height of the object. What is the distance between the object and the mirror if we know that the focal distance is equal to 0.2m?

Homework Equations


M = Yi/Yo = q/p
1/p+1/q=1/f

Yi= height of the image
Yo = height of the object
q = distance of the image
p= distance of the object
M = magnification
f = focal distance

The Attempt at a Solution



M = Yi/Yo = 0.25 since the image is 25% the height of the object.
Then, since M=q/p, I know the distance from the object to the mirror is 4 times the distance of the image to the mirror.
This is where I'm stuck.
 
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Phil123 said:

Homework Statement


An object is in front of a convex mirror. We then obtain an erect image whose height is equal to 25% of the height of the object. What is the distance between the object and the mirror if we know that the focal distance is equal to 0.2m?

Homework Equations


M = Yi/Yo = q/p
1/p+1/q=1/f

Yi= height of the image
Yo = height of the object
q = distance of the image
p= distance of the object
M = magnification
f = focal distance

The Attempt at a Solution



M = Yi/Yo = 0.25 since the image is 25% the height of the object.
Then, since M=q/p, I know the distance from the object to the mirror is 4 times the distance of the image to the mirror.
This is where I'm stuck.
Use the equation you included 1/p+1/q=1/f. Take care of the signs of focal length and image distance.
 

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