Are the Final Velocities of Two Blocks After an Elastic Collision Correct?

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SUMMARY

The final velocities of two blocks after an elastic collision have been calculated correctly using the formulas V1f = (m1 - m2) / (m1 + m2) * V1i and V2f = (2m1) / (m1 + m2) * V1i. For a 5 kg block (m1) traveling at 10 m/s colliding with a stationary 2 kg block (m2), the final velocities are V1f = 4.28 m/s and V2f = 14.29 m/s. A minor typing error was noted in the original post, where a parenthesis was mistakenly used instead of a division symbol.

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phunphysics2
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Greetings Fellow Physics lovers!

I was wondering if somebody could please check my work on this problem.

A 5 kg block traveling at 10 m/s collides into a stationary 2 kg block. Find the final velocities of the two blocks after the elastic collision.



V1f=(m1-m2)/(m1+m2) (V1i)

V2f= (2m1)/(m1+m2) (v1i)



V1f=(5-2)((5+2) (10) = 4.28 m/s

V2f=2(5)/(7) (10)= 14.29 m/s


Thanks for your help!
 
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phunphysics2 said:
Greetings Fellow Physics lovers!

I was wondering if somebody could please check my work on this problem.

A 5 kg block traveling at 10 m/s collides into a stationary 2 kg block. Find the final velocities of the two blocks after the elastic collision.



V1f=(m1-m2)/(m1+m2) (V1i)

V2f= (2m1)/(m1+m2) (v1i)



V1f=(5-2)((5+2) (10) = 4.28 m/s

V2f=2(5)/(7) (10)= 14.29 m/s


Thanks for your help!

It is correct, except the typing error of "(" instead of "/".

ehild
 

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