Find the impluse momentum of the sphere

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SUMMARY

The discussion centers on calculating the impulse momentum of a sphere with a mass of 0.4 kg, which moves along a circular trajectory with a radius of 2 m and an angular speed of 12 rad/s. Participants clarify that the term "impulse momentum" may refer to angular momentum, leading to confusion regarding the correct formula to use. The appropriate equations discussed include L = Iω = (2/5)mr²ω for a sphere and L = mr²ω for a point mass. It is concluded that without the radius of the sphere itself, the sphere can be treated as a point mass for this calculation.

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zade70
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Homework Statement


A sphere with mass 0.4 kg circles around a circular trajectory with ray 2 m and angular speed 12 rad/S. Which is the momentum of the impulse of the sphere?

Homework Equations


L=Iw=2/5mr^2w
w(angular speed)
or
L=mr^2w

The Attempt at a Solution


I think we should use the first formula because the I (inercy momentum) of sphere, but in the solution it is used L=mr^2w. Which is correct?
 
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The first would describe a sphere rotating around its center.
The second is correct if you have a point-mass.

For a sphere rotating around a point different from its center you need a sum of both, but keep in mind that the radius of the sphere is not the same as the radius of the rotation. If there is no radius given for the sphere itself, you cannot add this contribution. It can be negligible (if the sphere is small compared to the 2 meters).
 
zade70 said:
A sphere with mass 0.4 kg circles around a circular trajectory with ray 2 m and angular speed 12 rad/S. Which is the momentum of the impulse of the sphere?
You mean angular momentum, right? Are you told the radius of the sphere?
 
haruspex said:
You mean angular momentum, right? Are you told the radius of the sphere?
I don't know if the radius (ray) given is of the sphere
 
zade70 said:
I don't know if the radius (ray) given is of the sphere
You did not confirm whether you mean angular momentum.
It is not stated whether the sphere is rotating on its own axis. If it is executing a circle of radius 2m but retaining a constant orientation then its being a sphere is irrelevant. You can treat it as a point mass.
 
haruspex said:
You did not confirm whether you mean angular momentum.
It is not stated whether the sphere is rotating on its own axis. If it is executing a circle of radius 2m but retaining a constant orientation then its being a sphere is irrelevant. You can treat it as a point mass.
It says impulse momentum of sphere not angular. So we should take it s a point mass?
 
zade70 said:

Homework Statement


A sphere with mass 0.4 kg circles around a circular trajectory with ray 2 m and angular speed 12 rad/S. Which is the momentum of the impulse of the sphere?
In what language was the problem written?
In my language, (Hungarian) the same word is used both for ray of light and radius of circle, and also the angular momentum is called impulse momentum. But in English, use radius and angular momentum:
A sphere with mass 0.4 kg circles around a circular trajectory with radius of 2 m and angular speed 12 rad/S. What is the angular momentum of the sphere?
 
zade70 said:
It says impulse momentum of sphere not angular. So we should take it s a point mass?
I see @ehild points out that "impulse momentum" might mean angular momentum (strange though that may seem). But that does not help because you would also need to know (a) the radius of the sphere and (b) the rotation rate of the sphere on its axis (which need not be related to fhe rate of rotation of the sphere about the given axis).
 

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