- #1

- 9

- 1

Thread moved from the technical forums, so no HH Template is shown.

Warren falls over his tackle box and lands in a canoe 0.95 m below the side of the dock. Warren's mass is 70 kg and the canoe has a mass of 72 kg. Warren and the canoe move 1.73 m away from the dock in 1.005 seconds.

relating equations are

Vi = Vf - at

v = d/t

A = change in velocity/time interval

Work

I was thinking that I would need to take the the velocity from the end of the problem which is 1.73 m /1.005 s = 1.72 m/s. I think that is my Vf, i just want to make sure that is correct. Because if it was the Vf i still need to find the acceleration. Any help would be appreciated.

relating equations are

Vi = Vf - at

v = d/t

A = change in velocity/time interval

Work

I was thinking that I would need to take the the velocity from the end of the problem which is 1.73 m /1.005 s = 1.72 m/s. I think that is my Vf, i just want to make sure that is correct. Because if it was the Vf i still need to find the acceleration. Any help would be appreciated.